I have faced a problem simplifying this equation.
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I tried to solve it this way:
, but I just can't get the correct answer.
This equation is from high school course, so it must have quite a simple solution, so maybe you will be able to help me :)
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Kothas
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Square both sides of $\sqrt{y} + \sqrt{\frac{1}{y}} = 1$ to get $y + 2 + \frac{1}{y} = 1$; this is the quadratic $y^2 + y + 1 = 0$ with roots $y = \frac{2x+1}{x-1} = \frac{-1\pm\sqrt{-5}}{2}$. So there are no real values of $x$ for which the equation holds.
rogerl
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Now I get it, thank you :) – Kothas Jun 22 '14 at 16:24
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You're welcome. Don't forget to upvote and/or accept if you think it appropriate. – rogerl Jun 22 '14 at 16:26