Set S consists of all positive multiples of 5 that are less than 100, and set T consists of all positive multiples of 10 that are less than 100. The median of the numbers in set T is how much greater than the median of the numbers in set S?
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The number of multiples of $5$ which are less than $100$ is $\frac{95}{5}=19$. So, the median is the $\frac{19+1}{2}$-th term, which is $50$.
The number of multiples of $10$ which are less than $100$ is $\frac{90}{10} = 9$. By the same process, the median is $50$.
Therefore, the difference is $0$.
DSinghvi
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No, the median of $19$ things is the $\frac {19+1}2=10$th term. You have $9$ below, the median itself, and $9$ above. – Ross Millikan Jun 25 '14 at 16:25
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