0

50% of teens believe that we need to address the problem of climate change. If a random poll of 1500 teens was taken (about the size of the Gallup poll), what is the chance that its proportion would accurately reflect the population proportion within 3 percentage points?

Any help is appreciated, I know half of the sample is 750, so am I looking for the chances that within the sample it's between 48.5% and 51.5%?

Rosie E
  • 55
  • 8

1 Answers1

1

Note that this assumes you are not using the statistical ideas of normal distribution

What you want is that between 705 and 795. So you want the probability that that X teens choose yes out of 1500. Since there is a 50% chance for each teen, we can use binomial probability. Let's look at a small example: Suppose you flipped a coin 5 times and wanted the probability that it was heads twice. So we know there is a 50% chance of heads, and there are many ways this can work. We can have HHTTT, or HTHTT, just to name a few. In fact, there are 5 choose 2 ways of this working out, which uses some fancy combinations. And there is a .5^5 chance of each of the different ways occurring. So as a final result, you would want $.5^5 * (5 choose 2)$

For your question, you want not just that, but also for 3 Heads.

So you want $\sum_{n=705}^{795} [(1500 $ choose $ n)*.5^{1500}]$. There should exist a function on your calculator that will do this for you. If anyone knows how to LaTeX the (n choose r) formula, that would be helpful to this answer. Hope this helps you.

Thoth19
  • 829
  • Two questions. How did you know that what we want is between 705 and 795? The rest I follow. I'm also looking through my calculator for the function to solve this and am coming up empty, do you know where this would be, I have a TI-83. – Rosie E Jun 30 '14 at 05:12
  • 705 and 795 come from .471500 and .531500 respectively. We want how likely it is that the sample we choose will be between 47 and 53 percent and we know the sample size. so we can solve for how many people that makes which imo is easier to think about than percents – Thoth19 Jun 30 '14 at 09:45
  • I'm trying to solve this now using the central limit theorem. I have the formula and most of the variables, but how do I find the mean for this, would it be 50% since I expect half of teens to say yes? Also, how would I find the standard deviation? I apologize if this all seems very simple/obvious, I just want to make sure I really understand. – Rosie E Jun 30 '14 at 16:35