Hint: This appears to be about the Well-Ordering Principle, which states that every nonempty subset $D$ of the natural numbers $\mathbb N$ has a least element (where I assume that you define the natural numbers to start at $0$ instead of at $1$). That is, we know that if $D \subseteq \mathbb N$ and $D \neq \emptyset$, then:
$$
\exists y \in D \text{ such that } \forall x \in D,~ y \leq x
$$
Hence, if $y$ is allowed to be any natural number and if we want that inequality to be strict, then we want to exclude the possibility that $x = 0 \in D$ so that we can just take $y = 0$ to be the natural number that is strictly smaller than any other natural number.