All of the "topologies" contain $\mathbb{R}$ and $\phi$, so what you need to check is that if you take an arbitrary union of sets in each given $\tau$, the result is also in $\tau$, and the same for finite intersections.
As a clue on how to approach the question, I will tell you that the only actual topologies are $9$ and $10$. So you must show that $\tau_9,\tau_{10}$ are closed under arbitrary unions and finite intersections, and for each of the others, try to find sets whose union (or finite intersection) doesn't belong to the $\tau_x$
Edit: Upon request, here's some more details for $9)$:
Take any collection of sets $(-r_i,r_i),[-r_j,r_j]$ for $i \in I$, $j \in J$ some indexing sets. We aim to show that $U = \cup_{i\in I} (-r_i,r_i)\cup_{j\in J} [-r_j,r_j]$ is contained in $\tau_9$. What happens if one of $\{r_i : i \in I\},\{r_j:j \in J\}$ is unbounded? (Easy.) What happens otherwise? (Harder.)