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I have a MATLAB question. How can I calculate and subsequently plot the argument of

$$x(n) = e^{(0.1 + 0.3j)n}$$

Chris Taylor
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nikos
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1 Answers1

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n=1:3;
x=exp((0.1+i*0.3)*n);
p=angle(x)
plot(p)
cyborg
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