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The average of 21 members is 30. The largest number is 50. If we remove the largest number then the average of remaining numbers will be?

TooTone
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Khawar Zaman
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  • Try calculating the sum of all the numbers, and then, the sum of the remaining numbers. – JimmyK4542 Jul 22 '14 at 19:56
  • Welcome to Math.SE. In order for us to help you, it helps for you to give us an idea of what you've tried to far - that way we can tailor advice to your knowledge level – Mathmo123 Jul 22 '14 at 19:56
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    If the average out of $21$ members is $30$, the sum is $630$. When you remove the member with $50$, you have $20$ members whose sum is $580$, hence the average drops to $29$. – Jack D'Aurizio Jul 22 '14 at 20:13
  • I guess that comment can go as an answer! – MonK Jul 22 '14 at 20:51

1 Answers1

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The sum of the thirty numbers is $n \cdot \overline x= \color{blue}{21} \cdot \overline x$, where $\overline x$ is the average of the thirty numbers.

Edit: blue printed have been edited.

Then subtract the largest number from the result. After that, divide the new result by (n-1).

callculus42
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