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How can I get the derivative of the following formula with respect to X?

$$ g = \frac{X\exp({Y' X)} Z (Z)^{\exp{(Y'X)}}}{1-Z^{\exp{(Y'X)}}}$$

where X is a vector of unknown parameters and Y is a vector same length as X but known, such that for example if the length of parametr X is 2, we have $$X_1 *Y_1+X_2*Y_2+X_3*Y_3$$ Also Z is a vector which is known.

rose
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  • Do you need to compute $\frac{\partial g_j}{\partial x_i}$, where $X=(x_1,...,x_i,...,x_n)$ and $j\in 1,\cdots,n$? – Avitus Jul 25 '14 at 17:28
  • How would you define $Xexp(Y'X)Z$? In the middle you have a scalar ($exp(Y'X)$), but both $X$ and $Z$ are vectors. – Avitus Jul 25 '14 at 17:38

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