The Taylor series about 0 for the function $$f(x) = \left(\frac14 + x\right) ^ {-\frac{3}{2}}$$ is
$$f(x) = 8 - 48x+240x^2-1120x^3 + \dots$$
for $-\frac{1}4 < x <\frac14$
Use differentiation to find the Taylor series about $0$ for the function
$$g(x) = \left(\frac14+x\right)^{-\frac{5}2}$$ giving all terms up and including the one in $x^2$.