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Find the points of maximum and absolute minimum of the following function of two variables $$f(x,y)=\frac{\cosh (x-y)}{x}\left(e^{x}-x-1\right)$$ on the set: $$M=\left\{(x,y)\in \mathbb R^2 \ \Bigl|\ x+y\leq L\right\}$$ Let us initially extreme points internal to M, ie $$int(M)=\left\{(x,y)\in \mathbb R^2 \ \Bigl|\ x+y< L\right\}$$ and is simple to verify that $(0,0)$ is a saddle point.

For the extreme point in the boundary of M: $$\partial M=\left\{(x,y)\in \mathbb R^2 \ \Bigl|\ x+y = L\right\}$$ we apply the Lagrange multiplier method. Is correct the procedure?

Now I get some equations that (in my opinion) are impossible to solve in closed form. Or not?

What do you think?

Mark
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  • I would study the extrema of the function $g(x)=f(x, -x+L)$ and then classify them w.r.t. $f$. – Avitus Aug 05 '14 at 09:21

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