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How would I simplify a fraction that has a radical in it? For example:

$$\frac{\sqrt{2a^7b^2}}{{\sqrt{32b^3}}}$$

  • Have you tried combining the radicals into the radical of the fraction? – Paul Sundheim Aug 19 '14 at 01:29
  • It will depend on your standard for simplification. For example, are you allowed to write $b^{-1/2}$, or do you simplify that as $1/b^{1/2}$, or as $b^{1/2}/b$? – MPW Aug 19 '14 at 01:49
  • @MPW I would simplify to a fraction without any fractions being left in the numerator or denominator. – DaveTheMinion Aug 19 '14 at 10:58

2 Answers2

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$$\frac{\sqrt{2a^7b^2}}{\sqrt{32b^3}}=\frac{\sqrt{2}\sqrt{a^6}\sqrt{a}\sqrt{b^2}}{\sqrt{16}\sqrt{2}\sqrt{b^2}\sqrt{b}}=\frac{a^3\sqrt{a}}{4\sqrt{b}}$$

Hamed
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Hint:

$$\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$$

Kaj Hansen
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