I'm doing a physics E&M problem, but I'm stuck on a math part. I can't remember how to solve for x in this instance.
${x\over 2} = {0.04-x\over 5}$
I'm doing a physics E&M problem, but I'm stuck on a math part. I can't remember how to solve for x in this instance.
${x\over 2} = {0.04-x\over 5}$
HINT:
Multiply each side of the equation by $10$.
Add $2x$ to each side of the equation.
Divide each side of the equation by $7$.
Solve it like any other algebra problem like this. Isolate $x$ to one side and then make the necessary multiplications.
$\frac{x}{2}=\frac{0.04-x}{5} \Rightarrow \frac{x}{2}+\frac{x}{5}=\frac{0.04}{5} \\ \Rightarrow \frac{7x}{10}=\frac{0.04}{5} \Rightarrow x=\frac{10}{7}\times \frac{0.04}{5}$