$$z=f\left(x,y\right)=x^{2}\tan^{-1}\left(\frac{y}{x}\right)-y^{2}\tan^{-1}\left(\frac{x}{y}\right)$$
Prove that $$\frac{\partial^{2}f\left(x,y\right)}{\partial x\,\partial y}=\frac{x^{2}-y^{2}}{x^{2}+y^{2}}$$
$$z=f\left(x,y\right)=x^{2}\tan^{-1}\left(\frac{y}{x}\right)-y^{2}\tan^{-1}\left(\frac{x}{y}\right)$$
Prove that $$\frac{\partial^{2}f\left(x,y\right)}{\partial x\,\partial y}=\frac{x^{2}-y^{2}}{x^{2}+y^{2}}$$
The answer just hinges on performing the derivatives on one of the terms correctly, the other term is the same with the roles of $x$ and $y$ switched. You can also take the derivatives in either order. Start with the first term and see that the $y$ derivative is just:
$\frac{x^3}{y^2 + x^2}$
The answer is straight forward frome there.