Does the above image correctly mean "This is a 404 error?"
That is, does this
$$ \sum_{i = 47}^{54} $$
mean 404? Or should it just be this,
$$ \sum_{47}^{54} $$
without the equals?
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7It should be $$\sum_{i = 47}^{54} i$$ – Darth Geek Aug 25 '14 at 21:10
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1Strictly the sum would be $8error$ - what else would the summand be? – Mark Bennet Aug 25 '14 at 21:11
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@Mark why would it be 8? – Tim Aug 25 '14 at 21:11
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$47, 48, 49, 50, 51, 52, 53, 54$ - the sum covers $8$ integers $\dots$ – Mark Bennet Aug 25 '14 at 21:13
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@Darth Thanks, do add as an answer! – Tim Aug 25 '14 at 21:13
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1@Mark ahh okay, so what Darth says is correct! Thanks :) – Tim Aug 25 '14 at 21:13
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Indeed - you just have to add the right thing! – Mark Bennet Aug 25 '14 at 21:14
1 Answers
5
It should be $$\sum_{i = 47}^{54} i$$
Note that: $$\sum_{i = 47}^{54} i = (47 + 0) + (47 + 1) + \ldots + (47+7) =\\ 47·8 + (0+1+\ldots+7) = 47·8 + \frac{7·8}{2} = 404$$
As desired. This is what I think was intended but here are many more options, such as:
$$\sum_{i = 47}^{54} \frac{404}{8} = 404$$
$$\sum_{i = 47}^{54} (101-i) = 404$$
Darth Geek
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Yeah, I just found this wolfram|alpha widget - If you want you could edit to include it! – Tim Aug 25 '14 at 21:17