5

$(1,1)(3,9)(6,21)$

The way I figured that this should be solved is by finding the slope of: $(1,1)(3,9)$

Then, $(3,9)(6,21)$

Finally $(1,1)(6,21)$

Which are 4, 4,and 4 respectively. So I assume that they are collinear.

Am I correct? And if not, please provide me with an explanation as to what needs to be done to find the answer rather than a direct answer.

3 Answers3

1

What you checked is ok; in plane geometry if any two slopes from the point pairs are necessarily same, it is sufficient to conclude collinearity.

Narasimham
  • 40,495
0

As you're given three points yes it's correct.
There are more ways to find co-linearity:
Determinant method: If $$\det\left| \begin{array}{ccc}1 & 1 & 1 \\ 3 & 9 & 1 \\ 6 & 21 & 1 \end{array}\right|=0$$ It is colinear.
Using distance formula: if your points are A,B and C then, $$AB^2+BC^2=AC^2\ \ or\ \ AC^2+BC^2=AB^2\ \ or\ \ AB^2+AC^2=BC^2$$ means it is colinear

0

Yes, you are correct. It is sufficient to calculate only two slopes to decide that three points are collinear.

miracle173
  • 11,049