2

The formula for the average no. of objects in a box,when m objects are filled in n boxes $(m>n)$

is given by $[m/n]$ ,if $(m/n)\in \mathbb Z$

and $[m/n]+1$,if $(m/n)\notin \mathbb Z$ .

The thing I can't understand is why in the second case did we take $[m/n]+1$ and not $[m/n]$.

spectraa
  • 1,775

1 Answers1

1

This formula is incorrect. For example, if $m=6$, $n=5$, then perhaps four boxes have one object and one box has two objects. However $[m/n]+1=2$, so the "average no." is $2$.

The correct formula is $m/n$, with no floors, and no plus one, assuming "average" means "mean".

vadim123
  • 82,796