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Everyone. I am not sure how to start this problem. If anyone can show me a step by step process with an explanation I would appreciate it.

If $S= \{x_1,x_2,x_3,x_4\}$, let $f,g\in S_4$ be defined by: $$f:x_1\to x_2, x_2\to x_3, x_3\to x_4, x_4\to x_1$$ and: $$g:x_1\to x_2, x_2\to x_1, x_3\to x_3, x_4\to x_4$$

3 Answers3

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It's customary to use this notation

$$g=\begin{pmatrix}1&2&3&4\\2&1&3&4\end{pmatrix}=(12)\leftarrow\text{transposition}$$ so $$g^2=\operatorname{id}\quad;\quad g^3=g$$ and by the same method we have $$f=(1234)\leftarrow\text{cycle}$$ so $$f^2=(13)(24)$$

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Given $f(x)$:

  • $f(x_1)=x_2$
  • $f(x_2)=x_3$
  • $f(x_3)=x_4$
  • $f(x_4)=x_1$

Compute $f^2(x)$ as follows:

  • $f^2(x_1)=f(f(x_1))=f(x_2)=x_3$
  • $f^2(x_2)=f(f(x_2))=f(x_3)=x_4$
  • $f^2(x_3)=f(f(x_3))=f(x_4)=x_1$
  • $f^2(x_4)=f(f(x_4))=f(x_1)=x_2$

You can use this example in order to compute $g^2(x)$ and $g^3(x)$...

barak manos
  • 43,109
1

The multiplication on $S_{n}$ is defined as function composition thus $$ f^{2}(x)=f(f(x)),g^{3}(x)=g(g(g(x))) $$

etc'

Just evaluate the above terms at $x_{i}$ with $1\leq i\leq4$ to determine what permutations of $S_{4}$ they are

Belgi
  • 23,150