In how many ways can the letters of the word 'arrange' be arranged if the two r's and the two a's do not occur together?
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Total number of combinations: $\dbinom{7}{2}\cdot\dbinom{5}{2}\cdot\dbinom{3}{1}\cdot\dbinom{2}{1}\cdot\dbinom{1}{1}=1260$
Number of combinations with aa: $\dbinom{6}{2}\cdot\dbinom{4}{1}\cdot\dbinom{3}{1}\cdot\dbinom{2}{1}\cdot\dbinom{1}{1}=360$
Number of combinations with rr: $\dbinom{6}{2}\cdot\dbinom{4}{1}\cdot\dbinom{3}{1}=360$
Number of combinations with aa and rr: $\dbinom{5}{1}\cdot\dbinom{4}{1}\cdot\dbinom{3}{1}\cdot\dbinom{2}{1}\cdot\dbinom{1}{1}=120$
So the number of combinations without aa or rr is $1260-360-360+120=660$
barak manos
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aangrre. But what aboutaanrgre, is this valid or invalid? In other words, do you want to exclude only arrangements where both letters occur together, or also arrangements where either one of the letters occurs together? – barak manos Sep 17 '14 at 08:20