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Is there inequality of the type $e^x+e^y \le e^{x+y}$ or $e^x+e^y \ge e^{x+y}$

Boby
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1 Answers1

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Because $e^x$ is convex, you have $$e^{\frac{x+y}{2}}\le \frac{e^x+e^y}{2}$$ which can be rearranged as $$2\sqrt{e^{x+y}}\le e^x+e^y$$

vadim123
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