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We know by Riemann mapping theorem that for every connected, simply connected proper open subset $U$ of the complex plane, there exists a biholomorphic map $\phi:U\to \mathbb{D}$ (Where by $\mathbb{D}$ we mean the unit open disk). The proof of this theorem is too complicated.

Is there a simple proof for the similar question, when we are looking for homeomorphism or diffeomorphism instead of holomrphic function?

Hesam
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    I don't know if I would say the proof is too complicated. Certainly it is deep and on the long side, but it is actually a pretty nice proof. – Seth Sep 29 '14 at 17:51

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