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Suppose you are trying to get from one end $A$ of a terminal to the other end $B$. (For simplicity, assume the terminal is a one-dimensional line segment.) Some portions of the terminal have moving walkways (in both directions); other portions do not. Your walking speed is a constant $v$, but while on a walkway, it is boosted by the speed $u$ of the walkway for a net speed of $v+u$. (Obviously, given a choice, one would only take those walkways that are going in the direction one wishes to travel in.) Your objective is to get from $A$ to $B$ in the shortest time possible.

  1. Suppose you need to pause for some period of time, say to tie your shoe. Is it more efficient to do so while on a walkway, or off the walkway? Assume the period of time required is the same in both cases.
  2. Suppose you have a limited amount of energy available to run and increase your speed to a higher quantity $v'$ (or $v'+u$, if you are on a walkway). Is it more efficient to run while on a walkway, or off the walkway? Assume that the energy expenditure is the same in both cases.
  3. Do the answers to the above questions change if one takes into account the various effects of special relativity? (This is of course an academic question rather than a practical one. But presumably it should be the time in the airport frame that one wants to minimise, not time in one’s personal frame.)

What is the mathematically rigorous solution to this problem? All I come up with are based on personal intuitions.

UserX
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    This question is a straight copy from this page. There are over a hundred answers there already, some of them even attempting the relativistic case. – TonyK Oct 05 '14 at 15:03
  • I know it is, I stated it in the title. I can't find an adequately rigorous solution in the comments though. – UserX Oct 05 '14 at 15:12
  • Can you not find an adequately rigorous solution to any of the questions? One comment is: "for Q1, the total time = (time spent tying shoelace) + (time spent moving on solid ground) + (time spent moving on escalator). The first two terms are equal in each case." – what's not adequately rigorous about that? – Ben Millwood Nov 28 '15 at 06:39

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