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Question: Given a nonconstant polynomial P with at least one negative coefficient, then $(P(x))^m\forall m\in N^{+},m\ge 2$ with all coefficient is postive.

in other words:

Prove :There exsit real coefficient polynomial $$P(x)=a_{n}x^n+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0},n\ge 1$$ where there exsit some coefficient is negative.

and
such $$(P(x))^m=b_{nm}x^{nm}+\cdots+b_{1}x+b_{0},\forall m\in N^{+},m\ge 2$$

where $b_{i}>0,i=1,\cdots,nm$

I fell maybe this polynomial is not exsit,But I can't prove it? Thank you

My try:if let $$P(x)=x-1,\Longrightarrow (P(x))^2=x^2-2x+1,(P(x))^3=x^3-3x^2+3x+1,\cdots$$ this example is not such this condition

if $$P(x)=x^2-x+1,\Longrightarrow (P(x))^2=x^4-2x^3+3x^2-2x+1$$ also not such condition

math110
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1 Answers1

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$$(3x^4+3x^3-x^2+3x+3)^2=9x^8+18x^7+3x^6+12x^5+37x^4+12x^3+3x^2+18x+9$$ is an example that works for $m=2$. Maybe it works for all $m$.

Gerry Myerson
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