If u|t and v|t and gcd(u,v)=1, then prove that (uv)|t
I started by analyzing the definition of divisibility and I got that (uv)|t^2, but this doesn't help me.
Any advice would be appreciated. Thank you :)
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1Lemma: if $v\mid ab$ and $\gcd(v,b)=1$ then $v\mid a$. Application: $v\mid \frac{t}{u}u$ and $\gcd(v,u)=1\implies v\mid\frac{t}{u}$. – anon Oct 21 '14 at 01:35
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Nice work finding all these duplicates, @Goos! – Lord_Farin Jan 07 '15 at 18:10