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Prove by PMI $\gcd(f_n,f_{n+1}) = 1$ for all natural numbers $n$. $f_n$ represents the Fibonacci sequence.

Amzoti
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2 Answers2

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Three consecutive terms in a Fibonacci sequence can be written as $a,b,a+b$. If $d$ divides $b$ and $d$ divides $a+b$, then $d$ divides $a+b-b=a$.

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Hint: $\gcd(a,b)=\gcd(a-b,b)$.