Here's a problem from a 6th Grade textbook:
A project was carried out by a 3-man brigade working for 5 days and a 4-man brigade working for 4 days. $390 was paid for the whole project. How much was the first brigade paid if the productivity of all the workers is the same?
My attempt was to first calculate the whole effort needed for the project in $man*days$, which is $5*3 + 4*4 = 31man*days$. Then estimate how much one $man*day$ costs - $\frac {390} {31} dollars$. Therefore, the first brigade, which has made $15man*days$ effort, must receive $15* \frac {390} {31} dollars$. However, the "correct" answer in the answer key is $150 dollars$. I am almost sure that the answer key is wrong, but decided to ask just in case I'm missing something subtle or obvious.
P.S. I have no idea how to tag this question. Please suggest.