Can some one help me with this problem:
Let $f:R^2\rightarrow R^2$ be defined by $\displaystyle{f(x,y)=(e^{x+y},e^{x-y})}$
Find the area of the image of the region $\{(x,y) \in R^2 : 0<x,y<1 \}$ under the mapping f
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You can compute the Jacobian of your mapping ($2e^{2x}$) and integrate that over the unit square to get $e^2-1$. – Mark McClure Oct 26 '14 at 14:53
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@Mark McClure....will you explain that why the region is a unit square? – Nitin Uniyal Jun 18 '16 at 05:25