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I get the solution of $z^{2}+2z+5=0$

$z=-1+2i \;\; \overline {z}=-1-2i$

Robert Lewis
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Tony
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1 Answers1

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Hint : let $z=a+ib$ then in euler form $z=re^{i\theta }$

where $r=\sqrt {a^2+b^2}$ and $\theta=tan^{-1}({b/a})$

This link might help http://tutorial.math.lamar.edu/Extras/ComplexPrimer/Forms.aspx

Jasser
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