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Prove or disprove: Every bounded lattice is complete. It can be easily proved that every complete lattice is bounded. But is the converse true?

learner
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1 Answers1

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How about taking any bounded incomplete linear order like $\mathbb{Q}\cap [0,1]$? Alternatively take any incomplete Boolean algebra (for instance a field which is not a $\sigma$-field).

Tomasz Kania
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