True of false? If G and H are two groups with the same order and both are abelian, then they are isomorphic.
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Am implication of this is that every finite abelian group is isomorphic to some cyclic group, which is not true.
ncmathsadist
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$\textbf{HINT-}$ Consider $\mathbb{Z_4}$ and $\mathbb{Z_2 \times Z_2}$. So FALSE.
Bhaskar Vashishth
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Any finite abelian group is isomorphic to direct product of prime power orders. So I can apply this for these two groups we get they are not isomorphic. Because if G is cyclic and H is not.
Y2k walker
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