To deduce a value for just one value, we can pick the shortest path from one variable to the other; this will only require 3 of the equations. Let me explain:
If we have an equation like $e+d=150$, we can rearrange the equation to say $d=150-e$, and then claim that $e \rightarrow d$. By doing this, we find the shortest cycle using the equations you gave:
$$a \rightarrow d \rightarrow e \rightarrow a,$$
because of the following equations:
$$a+d=230,$$
$$e+d=150,$$
$$e+a=180.$$
Just using these three, we can isolate $a$:
$$a+d=230$$
$$a+(150-e)=230$$
$$a+(150-(180-a))=230$$
$$a+150-180+a=230$$
$$2a-30=230$$
$$a=130$$
From this point on, we can just plug $a=130$ into the system and find all other values.