Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

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IMO 1959 - Problem 2 - Simplification of square-root values

I have a question on how the simplification process goes for squaring square-roots and how absolute values interact with one another. Question is from IMO Math-Olympiad 1959 #2 $A = \sqrt{x + \sqrt{2x - 1}} + \sqrt{x - \sqrt{2x - 1}}$ $A^2 =…
Nick
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What is the range of $x$ satisfying the inequality $-x|x| > 4$ where $x$ is an integer?

The range according to me is x<-2. But I got to know that x>2 is also a possible solution. How can that be correct? P.S. I know that this is a simple question. But I couldn't find any existing question in the forum related to this. If there exists…
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Solve Absolute Inequation by Using Triangle Inequality Theorem

Solve $|5-x|<6-|x|$ by using triangle inequality theorem. I can solve this problem by using definition of absolute value and the solution is any numbers between $-\dfrac{1}{2}$ and $\dfrac{11}{2}$, but never solve it by using the triangle inequality…
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Properties of Absolute Value and Squaring Function

This seems to me to be a fairly elementary property, but it isn't what I've come into contact with before. Is it fair to say that, for any $x \in \mathbb{R}$, $\left \lvert x \right \rvert^2 = x^2$? This didn't seem correct to me until it was…
user465188
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Why use absolute value?

So, there’s this thing called absolute value, or a modulus function that basically says how far away any real number $n$ is from $0$. For example, $|2|=2$ because $2$ is $2$ units away from $0$. Furthermore, a negative number’s $($such as $-3)$…
user558017
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Solve $2^{|x+2|}-|2^{x+1}-1|=2^{x+1}+1$

Have three questions as stated below, that concern respectively with the interpretation of the result obtained (with some proof, if possible), and why my solution set is different than the book's .: The different absolute value terms are stated…
jiten
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Logic for solving absolute value equalities

For absolute value equalities, say $|x-a|=b$, my approach is : There are two cases, based on which the sign of the absolute value is taken. Case 1: If $x-a\ge b$, then $x-a\ge 0$; so for given interval $x\ge a+b$, $x = a+b$. Case 2: If $x-a\lt b$…
jiten
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whats the absolute time interval?

For the time interval $1< \lvert t+1 \rvert \leq 3 $ I am trying to solve for t to get my range to plot a function. I know $\lvert t+1 \rvert \leq 3 \iff -3\leq t+1 \leq 3 \iff -4 \leq t \leq 2$ And then $ \lvert t+1 \rvert > 1 $ becomes $t+1 >1…
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Modulus simplication for $x$

$||x-1|-2|=|x-3|$. Find the value of $x$. In my attempt I got the critical values of the expression as $1$ and $3$. But I’m not sure is we can just not consider the $2$ in the LHS. My steps are Case 1: when $x>3$, $x-1-2=x-3$, $0=0$ Case 2:…
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Prove that for $a, b \in \mathbb{R}$ $|a + b -a| \geq |a| - |b-a|$

Prove that for $a, b \in \mathbb{R}$ $|a + b -a| \geq |a| - |b-a|$ I'm not sure how to go about proving this, I can't seem to find any reasonable way to use the triangle inequality and this doesn't seem to follow immediately from the other…
Perturbative
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Simplify the expression $x+y+|x-y|$

In our lecture, we were ask to simplify the expression $x+y+|x-y|$. This is how I simplified it: If $x\ge y$, $|x-y|=x-y$ and $x+y+|x-y|=x+y+(x-y)=2x$. If $x
Joe
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Simple modulus question

Probably a very simple question but not 100% sure. If $$\lvert x-y \rvert = \lvert y-z \rvert$$ am I right in saying that $$z=x$$ ? Thanks
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Equation of first grade with absolute value

I have this statement: I) The equation: $|x - 5 | = 1$ I want to solve the equation, but I have a question. When I have the absolute value of an incognita and a number, $ | x - 5 | $. How do I proceed ? Should I eliminate the absolute value as a…
ESCM
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Performing operations involving absolute values

How do you perform operations involving absolute values? I want to avoid squaring them, is there any way to work around that? Suppose I want to solve $\frac{|x-120|\cdot|y-39|}{2}$, what should be the expressions equivalent? EDIT: apologies,…
John Glenn
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Do these two equations mean the same thing?

Do the equations $|x|
Aditi
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