Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

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Finding functions max and min (abs value)

I have the function $$g(x)=|x^2-x-2|$$ which is defined on $$-\frac{3}{2}\leq x\leq \frac{3}{2}$$ I am struggeling with that g(x) has absolute values wrapped around. I taught that I just draw the graph and flip the negative values upwards but that…
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Prove that positive and negative numbers with an absolute value with equations with a variable in bars, too, having two solutions.

I've read this and it's known that positive and negative numbers with an absolute value such as $|9|$ and $|-2|$ in an equation with a variable also in those bars on the other side have two solutions because the variable can be itself or the…
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Finding an absolute value

Instruction says Find |3 - $\sqrt{10}$| Given answer is $\sqrt{10}$ - 3 I cannot give an explanation.
Ness
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When is possible to ignore an absolute value

$e^{\frac{2}{x-1}\log\left|x-1\right|}+1\neq 0$ Since that this is an exponential function, this equation is verified $\forall x \in \mathbb{R}$? Or I have to consider the absolute value of the ligarithm? Note: these are not homework.
Overflowh
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Absolute value and credit card balance

I'm embarrassed to ask this question, but my child has the following homework question: "Use absolute value to describe the relationship between a negative credit card balance and the amount owed." I'm not sure for what it is they're looking. …
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Why I cannot do this: $|x| = \sqrt{x^2} = (x^2)^{1/2} = x^{2 \ \times \ 1/2} = x$

Why is it wrong? $$|x| = \sqrt{x^2} = (x^2)^{1/2} = x^{2 \ \times \ 1/2} = x$$
Will
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How to prove |a-b|≤|a|+|b|?

I am struggling with $$ |a-b|\leq |a|+|b|$$ Can anyone please help? Many thanks!
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How can the product of two arbitrary numbers lie between the two numbers in real line?

On simple deduction,I know a and b are of opposite sign and b has the positive value. The two numbers can be any arbitrary numbers. Now in the equation I have to solve,it will be that magnitude of x equals magnitude of ab. Absolute value of ab is…
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Insert absolute value to another absolute value

Not knowing anything about the values of $a,b$, is the next move legal? $$||a|-|b|| + |b| = | |a|-|b|+|b| |$$
McLovin
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Absolute value notation in $\lvert\,x\,\rvert$

I know that $\lvert x\rvert < 1$ can be rewritten as $-1 < x < 1$ What about $\lvert x\rvert > 1$? Can this also be rewritten as $-1 < x < 1$? Thanks
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Absolute value of a square root

Can anyone explain to me why: $$|\sqrt{5} - 5| = 5 - \sqrt{5}$$ Obviously I understand why the $5$ turns positive but I don't really get why the square root of $5$ turns negative?
conejo
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$|f(x)g(x)| = |(f(x)||g(x)|$

I was wondering if $|f(x)g(x)| = |f(x)| |(g(x)|$ is true all the time as in the case of real numbers. I was not convinced enough that that was true. But I can't think of any counterexample. Thank you.
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This is confusing for me. Help! What material should I search?

Find the values of $x$ such that $|x-2|=2-x$. How do I solve this?
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Is $a=b$ when $|a-b|=0$? If so, how can I prove it?

I was looking at another proof in my book which seemed to use this fact for granted. I am pretty sure it's right, but how could I prove that?
the24
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How do you draw the absolute value graph of $y = \vert 2x + 1 \vert + x - 3$?

I know that you draw an absolute value graph by writing the equation in the format of $y = a \vert x - p \vert + q$ and I know how to draw it from there, but what do you do when there is an $x$ value outside the absolute signs?
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