Questions tagged [absolute-value]

For questions about or involving the absolute value function also known as modulus function.

The absolute value function, usually denoted by $|x|$, is a function $\mathbb{R} \to [0, \infty)$ which can be defined in three equivalent ways:

  1. $|x| = \begin{cases}x &\ \text{if $x \ge 0$, and} \\ -x &\ \text{if $x < 0$.} \end{cases}$

  2. $|x| = \sqrt{x^2}$, and

  3. $|x| = \max \{x, -x\}$.

This definition extends to complex numbers as the square root of the norm: $|x+iy|=\sqrt{x^2+y^2}$. In both cases, the function may be interpreted geometrically as the distance of the input number from the origin.


More generally, an absolute value may be defined on an field (or integral domain) $k$ as a function $|\cdot | : k \to \mathbb{R}$ which satisfies the axioms

  1. (nonnegativity) $|x| \ge 0$ for all $x \in k$,

  2. (definiteness) $|x| = 0 \iff x = 0 \in k$,

  3. (multiplicativity) $|x y| = |x||y| $ for all $x,y\in k$ ), and

  4. (triangle inequality) $|x+y| \le |x| + |y|$ for all $x,y\in k$.

For example, if $p$ is a fixed prime number and $x \in \mathbb{Q}$, then there exists a unique $n \in \mathbb{Z}$ such that $x$ may be written as $$ x = p^n \frac{a}{b}, $$ where $\gcd(p, a) = \gcd(p, b) = 1$. The function which maps $x$ to $p^{-n}$ is an absolute value on $\mathbb{Q}$, called the $p$-adic absolute value.

3133 questions
0
votes
1 answer

Why can't critical value/transitional points approach be used to solve this question?

Consider the following question: What is the sum of all possible solutions of the equation $|x + 4|^2 - 10|x + 4| = 24$? The answer is $-8$. I was able get $-8$ by doing it the regular way - checking $10|x + 4|$ for positive and negative values.…
0
votes
1 answer

Differential Equations: When do constants combine to be another constant?

I'm trying to isolate $y$. I have a constant times a negative one? Do I ignore the negative and leave is as a constant? Here's what I'm working with... $$|(6-2(y^3))| = ke^{-3\times2}$$ For a positive portion: $6-2(y^3) = ke^{-3\times-2}$ For…
Alex M
  • 11
0
votes
1 answer

Does there exist a perfect square in the form: $|x^2+52x|$, where $x\in \Bbb Z$?

Does there exist a perfect square in the form: $|x^2+52x|$, where $x\in \Bbb Z$? $x<0,x\neq-52$
0
votes
0 answers

Is it always possible to define an absolute value in an ordered field?

I am trying to show (not sure if possible) that i can generalize all basic arithmetic operations between limits of sequences of real numbers to any ordered field, so i need to build a generalized notion of absolute value. The reason why i am asking…
la flaca
  • 2,593
0
votes
2 answers

Inequality with absolute value.

Show that $\forall a,b\in \mathbb{R}$: $$ \left| \frac{a}{1+a^2} - \frac{b}{1+b^2} \right| \leq |a-b| $$ Being honest, I do not know where to start (apart from common denominator form) and would appreciate any help. Thanks in advance!
Mat Dyl
  • 511
0
votes
2 answers

Square divided by absolute value

First time posting on Math SE, with kind of a basic algebra question. Question Does the relation: $$\dfrac{(ab)^2}{|ab|} = \left|ab\right|$$ with $a,b \in \mathbb{R_{\ne 0}}$ always hold? It seems trivial to me, but Wolfram Alpha gives me a strange…
UJIN
  • 103
0
votes
2 answers

One absolute value inside of another absolute value in the equation

Let's say we have an equation: $||x|-2| = |2|x|+4|$ How does one go solving it? Symbolab says that it currently doesn't support step by step explanation for this problem, so I would really appreciate if someone could do it!
0
votes
4 answers

solving absolute value equation 2

My question is : Solve simultaneously- $$\left\{\begin{align*}&|x-1|+|y-2|=1\\&y = 3-|x-1|\end{align*}\right.$$ I tried to solve this question by the method told by Marvis as I had understood that method (its here: Solve an absolute value equation…
mgh
  • 1,005
  • 2
  • 10
  • 22
0
votes
3 answers

How can we prove that $\sqrt{ x^{2} }$ is equals to $|x|$?

I used to use this equality at school. But now in my books of Analysis this property is not mentioned. Is this maybe incorrect?
GniruT
  • 977
0
votes
1 answer

Why does my book say that "since a major change takes place at (1,1), the expression in the absolute value should equal to zero at x=1?

Question I am referring to: Why does the absolute value portion of the expression of the function this graph corresponds to has to be 0 when x=1? Here are the five choices:
0
votes
3 answers

Some confusion with absolute value

Today at a math lecture, I solved the equation $|x+1|+|x-1|+|x|=4$ by using elementary arithmetic. But my professor did it a little bit differently: I didn`t pay attention to the teacher's method,because I thought that I could understand it, but…
0
votes
1 answer

why it is not continuous for a absolute value division?

the question is : is y=|x-1|/(x-1)continuous on (-infi, +infi): I am wondering why this equation is not continuous when x = 1 I think when x=1, y will be 1
0
votes
3 answers

Polynomial equations with absolute values

How can I solve: $x^2 + 2|x| - 3 = 0$ ? My attempt: $|x| = \frac{3 - x^2}{2}$ $x = \pm \frac{3 - x^2}{2}$ $x^2 \pm 2x - 3 = 0$ The solutions to this 2nd degree polynomial is $x_1 = -3$ $x_2 = 1$ $x_3 = -1$ $x_4 = 3$ However, only $-1$ and $1$ are…
0
votes
1 answer

2nd derivative of a functions absolute value

So on wolfram alpha I am told that if $y=y\left ( x \right )$ then $\frac{d^{2}}{dx^{2}} \left | y \right |= \frac{y}{\left | y \right |}y^{''}+2\delta \left ( y \right )y^{'2} $ See it at this link But when I attempt to prove it myself I…
0
votes
1 answer

Is there a number whose absolute value is negative?

I've recently started to think about this, and I'm sure a couple of you out there have, too. In Algebra, we learned that $|x|\geq0$, no matter what number you plug in for $x$. For example: $$|-5|=5\geq0$$ We also learned that $x^2\geq0$. For…
Jason Chen
  • 1,153