Questions tagged [abstract-algebra]

For questions about monoids, groups, rings, modules, fields, vector spaces, algebras over fields, various types of lattices, and other such algebraic objects. Associate with related tags like [group-theory], [ring-theory], [modules], etc. as necessary to clarify which topic of abstract algebra is most related to your question and help other users when searching.

Abstract algebra is the study of algebraic objects, i.e. sets endowed with one or more operations on the elements of those sets. In particular, the study of abstract algebra considers the algebraic structures and properties of which such operations induce. It can be considered as the generalization of the study of the algebraic structure of the integers and real numbers (arithmetic), or the study of matrices and vector spaces (linear algebra).

Some algebraic objects are monoids, groups, rings, fields, vector spaces, modules, algebras, and categories, among many other less prominent objects.

Examples

  1. The set of non-negative integers $\mathbb{N} = \{0,1,2,3,\dotsc\}$ is a monoid under the operation $+$.

  2. The integers $\mathbb{Z} = \{\dotsc,-1,0,1,\dotsc\}$ under the binary operation of $+$ form a group.

  3. Furthermore, $\mathbb{Z}$ has the structure of a ring when you consider it as being equipped with both addition and multiplication.

  4. The real numbers $\mathbb{R}$ with their usual addition and multiplication form a field.

  5. The set of $n\times n$ matrices with entries in $\mathbb{R}$ with matrix addition and multiplication form a ring.

  6. The set of $1\times n$ vectors over the real numbers, with vector addition, and multiplication by elements of the $n\times n$ real matrices on the right are an example of a module for the ring of matrices.

In addition to studying the objects themselves, abstract algebra considers homomorphisms between the objects and various constructions and tools, which are useful for studying the objects.

85022 questions
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Why is $\mathbb{Z} [\sqrt{24}] \ne \mathbb{Z} [\sqrt{6}]$?

Why is $\mathbb{Z} [\sqrt{24}] \ne \mathbb{Z} [\sqrt{6}]$, while $\mathbb{Q} (\sqrt{24}) = \mathbb{Q} (\sqrt{6})$ ? (Just guessing, is there some implicit division operation taking $2 = \sqrt{4}$ out from under the $\sqrt{}$ which you can't do in…
user12802
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Prove that field of complex numbers cannot be equipped with an order relation

Please guide me in this problem. I am confused about whether its asking that having the relation $z>0$ does not satisfy the order axioms. Any help would be really appreciated. Thanks!
uh1
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Is it possible that $\text{lcm}(zx, zy)$ exists but $\text{lcm}(x, y)$ not?

Is it possible to find an example of an integral domain $D$ and a pair of non-zero elements $x$ and $y$ in $D$ such that $\text{lcm}(zx, zy)$ exists for some non-zero element $z$ in $D$ but $\text{lcm}(x, y)$ does not? Definition of least common…
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Is associativity implicated by commutativity

I definitely feel like an idiot because of the fact that I have to ask you the following question, but anyway I just don't know any other option. If just proven two things which are the opposites of each other, so at least one of my proofs have to…
Dominik
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Tensor product and exterior algebra

I want to show that there is a unique $R$-module isomorphism $M\otimes_{R}N\cong N\otimes_{R}M$, which sends $m\otimes n $ to $n\otimes m$. My idea is to show the map is onto and injective, then how to show its uniqueness? The second question is…
user53800
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How to prove that $\mathbb R [x]$ is a UFD

I could not believe that my professor asked this on the exam especially since this is intro-level abstract algebra. My idea was to somehow find a norm function and use the inequality $N(r) < N(d)$ in $m = qd + r$. I erased that and said: "since we…
Low Scores
  • 4,565
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How do we come up with the idea in the proof of $x^4+1$ is irreducible over $\Bbb Z$ by tranfer into $(x+1)^4+1$?

$x^4+1$ is irreducible over $\Bbb Z$ (hence $\Bbb Q$). The proof I saw is to try transforming it into $(x+1)^4+1=x^4+4x^3+6x^2+4x+2$ and use the Eisenstein criterion with prime $2$. I can understand the proof. However, how do we come up with this…
Eric
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Irreducibility of a polynomial

For $a,b_{1},b_{2} \dots b_{n} \in \mathbb{Z}$, $a>0$ and $b_{i}
Mykie
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Example of non-associative composition of morphisms

Is there any example showing that the composition of morphisms is not necessarily associative?
Jojo
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Ring Automorphisms and Roots of Monic Polynomials

I have the following problem: Let $R$ be a commutative ring with identity and $\phi: R \rightarrow R$ a ring automorphism. If $F=\lbrace r\in R | \phi(r)=r \rbrace$, show that $\phi^2$ being the identity map implies each element of $R$ is the root…
Frank White
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Group with more than one element and with no proper, nontrivial sub groups must have prime order.

I want to show that if $G$ is a group with more than one element, and that $G$ has no proper non-trivial subgroups. Prove that $|G|$ is prime. (Do not assume at the outset that |G| is finite). My question is not that how to prove it. I am saying…
Reader
  • 1,353
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Solving $x^{3} - 2 = 0$ and the field $\mathbb{Q}(\sqrt[3]{2})$

Let's start with a simple polynomial $f(x) = x^{3} - 2 \in \mathbb{Q}[x]$. It is known that $f$ is irreducible in $\mathbb{Q}[x]$ and hence without any further information (i.e. working in field $\mathbb{Q}$ and ring $\mathbb{Q}[x]$) we can not…
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is equivalence classes the same thing as cosets?

In abstract algebra (modern algebra), is the equivalence classes the same thing as cosets? In the lecture notes that I have, it seems as though they are but is it a universal rule for the equivalence classes to mean the same thing cosets? or is the…
jaghori
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What is $\mathbb{Z}[x]/(x,x^2+1)$ isomorphic to?

Consider the quotient ring $\mathbb{Z}[x]/(x,x^2+1)$. Taking the quotient by $(x)$ first, we get a ring that is isomorphic to $\mathbb{Z}$ by setting the relation $x=0$. Applying the relation, $(x^2+1)$ becomes $(1)$, so the quotient ring is…
6
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Dimension of a simple algebra over its center

Let $A$ be a finite dimensional simple algebra over a field $k$. Denote by $K$ the center of $A$. Why the dimension of $A$ over $K$ is a square?
unknown
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