Questions tagged [abstract-algebra]

For questions about monoids, groups, rings, modules, fields, vector spaces, algebras over fields, various types of lattices, and other such algebraic objects. Associate with related tags like [group-theory], [ring-theory], [modules], etc. as necessary to clarify which topic of abstract algebra is most related to your question and help other users when searching.

Abstract algebra is the study of algebraic objects, i.e. sets endowed with one or more operations on the elements of those sets. In particular, the study of abstract algebra considers the algebraic structures and properties of which such operations induce. It can be considered as the generalization of the study of the algebraic structure of the integers and real numbers (arithmetic), or the study of matrices and vector spaces (linear algebra).

Some algebraic objects are monoids, groups, rings, fields, vector spaces, modules, algebras, and categories, among many other less prominent objects.

Examples

  1. The set of non-negative integers $\mathbb{N} = \{0,1,2,3,\dotsc\}$ is a monoid under the operation $+$.

  2. The integers $\mathbb{Z} = \{\dotsc,-1,0,1,\dotsc\}$ under the binary operation of $+$ form a group.

  3. Furthermore, $\mathbb{Z}$ has the structure of a ring when you consider it as being equipped with both addition and multiplication.

  4. The real numbers $\mathbb{R}$ with their usual addition and multiplication form a field.

  5. The set of $n\times n$ matrices with entries in $\mathbb{R}$ with matrix addition and multiplication form a ring.

  6. The set of $1\times n$ vectors over the real numbers, with vector addition, and multiplication by elements of the $n\times n$ real matrices on the right are an example of a module for the ring of matrices.

In addition to studying the objects themselves, abstract algebra considers homomorphisms between the objects and various constructions and tools, which are useful for studying the objects.

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$F[x^2,x^3] $ (subring of $F[x]$ with no linear term $x^1)$ is not a UFD

My question pertains to this link (the content of which has been included below in the most recent edit) The ring of polynomials over a field with no linear term is not a UFD Let $F$ be a field. Prove that the subset $R \subseteq F[x]$ …
The Chaz 2.0
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How to show that this ring has no zero divisors?

Let $R$ be a finite ring that satisfies the following conditions: (1) For any $x\in R$, if $x\ne 0$ then $x^2\ne 0$. (2) There exists at most one nonzero element $y\in R$ that satisfies $y^2=y$. How can we show that $R$ has no zero divisors?
Nirvanacs
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Permutation group S8

In symmetric group S8, there are two permutations namely a=(147)(258) and b=(14)(2578). We are to find the no of such permutations say 's' such that as=sb. I am trying to use the tool of orders of permutations a and b which I got 3 and 4…
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Quotients of semisimple algebras

Given two $k$-algebras $A$ and $B$ and a surjection $A\to B$, then every $B$-module is also an $A$-module. Can we use this to show that quotients of semisimple algebras are semisimple? An algebra $A$ is said to be semisimple if every $A$-module is a…
user500228
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divisor of zero and an invertible element in $\mathbb Z_8[x]$

Find an example of a divisor of zero and an invertible element in $\mathbb Z_8[x]$. (Find nonconstant examples). So I've read around on this site and through other question and it seems that any unit or zero divisors of $R$ will also be a unit or…
K Math
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Prove $\text{Hom} (Z, \ker(f, g)) ≃ \ker(\text{Hom} (Z, X) ⇉ \text{Hom} (Z, Y ))$ for sets

I just started reading some Schapira notes on Algebra and Topology. Statement 1.7 is the following: Hom $(Z, \ker(f, g)) ≃ \ker(\text{Hom} (Z, X) ⇉ \text{Hom} (Z, Y ))$ where: $Ker(f, g) = \{x ∈ X; f(x) = g(x)\}$ I tried verifying this myself by…
Casebash
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For $G$ a group, if $|G| = n$, $n$ composite, will $G$ have a proper subgroup?

I can see how it is indeed possible that $G$ has a proper subgroup i.e. possibly $n = km$ and there is an element of order $k$ that generates a cyclic proper subgroup, but I am trying to see why this must necessarily be the case. My argument goes as…
Moderat
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Ideals of Formal Power Series

I realize that there have been several answers to why $(t^a)$ is an ideal for the formal power series, but I was wondering why $(t+1)$ isn't an ideal? I'm rather new to the concept of ideals, so any help is appreciated! $(t+1)$ means the ideal…
mathtm
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Do unity elements of a ring form a ring?

i am wondering if the unity elements of a ring form a ring ? In other words do they form an abelian group under addition ? I have tryied but i have not reached to a conclusive answer. Thanks for any comment.
user249018
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Let $m$ be a fixed integer. If $x^m \in H$ for every $x \in G$, then the order of every element of $G/H$ is a divisor of m.

G is a group and H is a normal subgroup of G. Let $m$ be a fixed integer. If $x^m \in H$ for every $x \in G$, then the order of every element of $G/H$ is a divisor of m. I am getting quite confused by this question and I attribute it to my very thin…
JxxYsde3
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$\mathbb{C}^\times$ mod roots of unity isomorphic to $\mathbb{C}^\times$

Let $H = \langle i \rangle =\{ i, -1, -i, 1 \}\le \mathbb{C}^\times$. Then is $\mathbb{C}^\times/H$ isomorphic to $\mathbb{C}^\times$? I don't think there exists an isomorphism $\varphi : \mathbb{C}^\times \to \mathbb{C}^\times/H$ because for…
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disjoint cycles, length of cycle and order of their product

Let $\sigma_1,\dots , \sigma_t$ be disjoint cycles in $S_n$ of lengths $l_1, \dots, l_t$ and $$ \sigma=\sigma_1 * \dots * \sigma_t.$$ Determine the order of $\sigma$ in terms of $l_1,\dots ,l_t$ I believe the answer is $ \mathrm{lcm} ( l_1,\dots…
Tiger Blood
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Subring of rationals with a prime denominator question.

This problem is coming from an exam review. Let $p$ be a prime number and let $\mathbb{Z}_p$ denote the set of all $x\in \mathbb{Q}$ which can be written as fractions whose denominator is not divisible by $p$. Show that if $x \in \mathbb{Q}$, then…
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If H and K are two normal subgroups of a group G .If the order of H and the order of K are relatively prime.prove that hk=kh

My answer is : let $h= gxg^{-1}$ in $H$ for $x$ in $H $ and $k= gyg^{-1}$ in $K$ for $y$ in $K$ $hk =(gxg^{-1})(gyg^{-1})=g (xy) g^{-1}$ But $xy$ in $HK$. hence $HK$ is normal in $G$ i.e . $aHK =HKa$ $ahk=hka$ And w.r.t the order of $H=p$ and…
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Is $\mathbb{Z}[x]/\langle x-3\rangle$ a field or not?

Is $\mathbb{Z}[x]/\langle x-3\rangle$ a field? Answer: Since $x-3$ is irreducible in $\mathbb{Z}[x]$, we have $\mathbb{Z}[x]/\langle x-3\rangle$ a field. But I know that $\langle x-3\rangle$ is not a maximal ideal. Thus, $\mathbb{Z}[x]/\langle…
MAS
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