Questions tagged [algebraic-equations]

Use this tag for questions related to solving equations involving polynomials.

An algebraic equation is an equation of the form $P = 0$ where $P$ is a polynomial with coefficients in some field, often the field of rational numbers.

For most authors, an algebraic equation is univariate, which means that it involves only one variable. On the other hand, a polynomial equation may involve several variables, in which case it is called multivariate and polynomial equation is usually preferred to algebraic equation. For example, $$x^5 - 3x + 1 = 0$$ is an algebraic equation with integer coefficients, and $$y^4 +\frac{xy}2 = \frac{x^3}3 - xy^2 + y^2 - \frac17$$ is a multivariate polynomial equation with rational coefficients.

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Problem Following Algebra Steps

I am trying to follow along an answer to a particular question and don't understand one of the steps taken. I don't understand how they got from step 3 to step 4? The steps can be seen below. I think they have divided both sides by $R_1$ which is…
David777
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Problem Following Along Algebra Steps

I have been given a question with the solution. However I am having trouble following the maths steps that have been taken in the solution. I'm unsure how they have gotten from step 1 to step 2, shown below: EDIT... Note that there are two…
David777
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Solve $(1+x)^2=A\sqrt{1+Cx}$ for $x$.

$x>0$, $A>0$ and $C>1$. I am trying to come up with a closed form expression for $x$, even if it is an approximation. Any help appreciated.
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Solving algebraic equations involving factorials - without trial and error.

The question is defined as follows: $$\frac{(x!)^3}{x}-1=3455$$ I first did the basics which was getting rid of the 1 onto the left and getting rid of the $x$, then I factorised both sides to get an expression as seen below: $$x!=3456^{1/3}\cdot…
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Equations of Value Unknown interest rate

i have two question in some assessments, both based on "Equations of Value Unknown interest rate" and two irregular contributions. I've been over the textbook, and looking along time on line found very little. the problems are such that person x…
Zepalz
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Variation of equation algebra h/5+0.6=2

In the equation h/5+0.6=2 We can solve by subtracting both side with 0.6 then multiply by 5. 7 will be the answer which is correct. But if we first multiple h/5 with 5 on other side 2*5 we get h+0.6=10 after solving this we get 9.4 wich if we put…
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Solve $3^x+x^3=17.$

It's a question I find a bit difficult to solve, and the question is: $$3^x+x^3=17.$$
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Confused on what steps make this equality

The solutions manual gives this equality without an explanation (as usual); I've been stuck at this for a good while and don't feel like wasting any more…
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