Questions tagged [arzela-ascoli]

The Arzela-Ascoli theorem is a fundamental result of mathematical analysis giving necessary and sufficient conditions to decide whether every sequence of a given family of real-valued continuous functions defined on a closed and bounded interval has a uniformly convergent subsequence. The main condition is the equicontinuity of the family of functions. The theorem is the basis of many proofs in mathematics. Use this tag alongside (real-analysis).

Consider a sequence of real-valued continuous functions $\{ f_n\}_{n\in \mathbb{N}}$ defined on a closed and bounded interval $[a, b]$ of the real line. If this sequence is uniformly bounded and equicontinuous, then there exists a subsequence $(f_{n_k})_k$ that converges uniformly. The converse is also true, in the sense that if every subsequence of $\{f_n\}$ itself has a uniformly convergent subsequence, then $\{f_n\}$ is uniformly bounded and equicontinuous.

222 questions
0
votes
0 answers

uniform boundedness can be relaxed to pointwise boundedness in Arzela ascoli theorem?

Let $C(X)$ be the space of continuous functions with the usual norm. $X$ be a compact metric space. The Arzela Ascolis theorem says: A subset $S$ of $C(X)$ is compact iff it is uniformly bounded and equicontinuous at any point of $x$. I think the…
0
votes
1 answer

On the conditions of Arzela Ascoli theorem

Let $X$ be a compact metric space. Let $F\subseteq C(X;\mathbb{R})$ be a family of functions. Then according to Arzela Ascoli $F$ is compact if and only if $F$ is equicontinuous at any point $t$ and $F$ is uniformly bounded. But I think uniform…
0
votes
1 answer

The union of a sequence of funtions and its convergent point

If $\{h_n\}_{n∈N} ⊂ C ([a, b])$ is $\| \cdot \|_{\infty}$ convergent to $h$, then $A ={h_n}∪{h}$ is $\| \cdot \|_∞$-compact, $\|\cdot \|_∞$-closed, $\| \cdot \|_∞$-bounded and uniformly equicontinuous. Is it proved in the same way that I prove $A$…