Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
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Is it allowed to write $\binom{n}{n+1}$ = 0?

For ex. $\binom{n}{n}$ = $\binom{n-1}{n-1}$ + $\binom{n-1}{n}$ according to the rule $\binom{n}{i}$ = $\binom{n-1}{i-1}$ + $\binom{n-1}{i}$
RM777
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Value of$ \sum^{50}_{k=1}(49+k)! \cdot (50-k)!\cdot (2k-1)$

Finding value of $$\sum^{50}_{k=1}\frac{\binom{50+k}{k}\cdot (2k-1)}{\binom{50}{k}\cdot (50+k)}.$$ Try: Let $$S = \sum^{50}_{k=1}\frac{(50+k)!}{50! \times k!}\times \frac{k! \times (50-k)!}{50!}\cdot \frac{(2k-1)}{(50+k)}$$ $$S =…
DXT
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Binomial summations

The given answer is zero. I tried adjusting the coefficients, changing to binomial co-efficients. Like $99C_r$but still the inside terms, i am not able to adjust.
maveric
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Prove using combinatorial argument $\binom{n}{0}.\binom{n}{2}+ \binom{n}{1}.\binom{n}{3}+\cdots+ \binom{n}{n-2}.\binom{n}{n}$

How can I prove it using combinatorial argument $$ \binom n0\binom n2 + \binom n1\binom n3 + \cdots + \binom{n}{n-2}\binom nn = \binom {2n}{n-2} $$ Sorry friends I have edited it
juantheron
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oreder pair of natural number in binomial coefficient

Finding all ordered pair of natural number $(n,r)$ for which $\displaystyle \binom{n}{r} = 240$ Try: $$\binom{n}{r}=\binom{n}{n-r}=240$$ For $n=240$ and $r=1.$ we have $\displaystyle \binom{240}{1}=240$ For $n=240$ and $r=239.$ we have…
DXT
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Calculate central q-Binomial coefficient

Is there any way to calculate the central q-Binomial coefficient efficiently. For example, $$\binom{2n}{n}_1=\frac{(2n)!}{(n!)^2}$$ First few values of $\binom{2n}{n}_2$ are $1,3,35,1395,200787,109221651$ First few values of $\binom{2n}{n}_3$ are…
piepie
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Find the coefficient of $x^9$ in the expansion of $(1+x)(1+x^2)(1+x^3)...(1+x^{100})$

The coefficient of $x^9$ in the expansion of $(1+x)(1+x^2)(1+x^3)...(1+x^{100})$. I tried the following concept, how to sum 9 using 1-9 only without repetition. 1:9, 2:1+8,3:7+2, 4: 6+3, 5: 5+4, 6:1+2+6 ,7:1+3+5, 8:2+3+4 The answer is 8. How will it…
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Binomial coefficient modulo

It is well known that $ \gcd(n,r) = 1 \implies \binom{n}{r} \equiv 0 \mod n $ Then my doubt is that is there any general formula if $\gcd(n,r) \ne 1$ I.e., $$r \ne 0 \land r \ne n \land \gcd(n,r) \ne 1 \implies \binom{n}{r} \equiv ? \mod n$$ If…
hanugm
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How many triangles can be formed in a 4 x 3 rectangle?

Question: Twenty lattice points are arranged along the edges of a $4 \times3$ rectangles as shown. How many triangles have all three of their vertices among these points? I started off with getting the total number of points possible, which is…
Crescendo
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Property of Binomial Coefficient

I have a "must be trivial" problem which I could not solve. Prove the following relation of binomial coefficients, if true: $$\sum_{k=1}^{n}{2n+1 \choose k}=2^{2n}-1$$ P.S. Though this is not homework, I appreciate any hints rather than explicit…
007resu
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Number of non negative integer solution of the equation $x+y+z=n$

Total number of non negative integer solution of the equation $x+y+z=n$ subjected to the condition $x\leq y \leq z.$ Try:if $x=0$ Then we have $y+z=n$ If $x=1$ Then we have $y+z=n-1$ .....if $x=n$ Then we have $y+z=0$ so $x=y=0$ Could some help me…
DXT
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Why is n a power of two for n over k even

If $\binom{n}{k}$ is even for every $1 \le k \lt n$, $n$ has to be a power of two. I'm searching for an elementary way to proof this.
mathbee
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product of binomial coefficients taken some or all at atime

If $\binom{n}{0} , \binom{n}{1} , \binom{n}{2} , \binom{n}{2} .... \binom{n}{n}$ denote the binomial coefficients in the expansion of ${(1+1)}^n$ then what is the difference between $$\sum_{r=0}^{n} \sum_{s=0}^{n} \binom{n}{r}\binom{n}{s}$$ and…
Aditi
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Evaluate $\sum^{n}_{k=1}\sum^{k}_{r=0}r\binom{n}{r}$

Evaluate the summation $$\sum^{n}_{k=1}\sum^{k}_{r=0}r\binom{n}{r}$$ $\bf{Attempt:}$ From $$\sum^{n}_{k=1}\sum^{k}_{r=0}r\binom{n}{r} = \sum^{n}_{k=1}\sum^{k}_{r=0}\left[r\cdot \frac{n}{r}\binom{n-1}{r-1}\right] =…
DXT
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Evaluate ${2n\choose 0} - {2n-1\choose 1} + {2n-2\choose 2} - \ \cdots \ (-1)^n{n\choose n}$

Possible Duplicate: How to compute $\sum\limits_{k=0}^n (-1)^k{2n-k\choose k}$? Evaluate ${2n\choose 0} - {2n-1\choose 1} + {2n-2\choose 2} - \ \cdots \ (-1)^n{n\choose n}$ The required sum is the coefficient of $x^n$ in $x^n(1-x)^{2n} +…
Saurabh
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