Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

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Binomial theorem - Positive integers solution

I'm having the following assignment: For which positive integer $n$ will the equations $$ x_1 + x_2 + x_3 + \ldots + x_{19} = n \tag{1}$$ $$ y_1 + y_2 + y_3 + \ldots + y_{64} = n \tag{2}$$ have the same number of positive integer solutions? I've…
Daniel B
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How to prove that $\sum_{i-is-even}^n \binom{n}{i} = \sum_{i-is-odd}^n \binom{n}{i}$

I need to prove that $\sum_{i-is-even}^n \binom{n}{i} = \sum_{i-is-odd}^n \binom{n}{i}$ i starts from 0. I succeeded proving this for odd n. But how to prove it for even n's?
TheLogicGuy
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Find the co-efficient of $x^{18}$ in the expansion of $(x+1)(x+2)...(x+10)(2x+1)(2x+3)...(2x+19)$.

Find the co-efficient of $x^{18}$ in the expansion of $$(x+1)(x+2)...(x+10)(2x+1)(2x+3)...(2x+19)$$ What I've done : $$ (x+1)(x+2)...(x+10)(2x+1)(2x+3)...(2x+19) \\ =\frac{(2x+1)(2x+2)(2x+3)...(2x+20)}{2^{10}} $$ I can't think of any way to find…
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Find remainder in binomial expression

In the question how they got $\lambda = 2^{1008}$?
hey
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Find the sum of this series of coefficients of $(1+x+x^2)^n$.

If $$ (1+x+x^2)^n=\sum_{r=0}^{2n}a_rx^r $$ then find the sum of : $$ a_0^2-a_1^2+a_2^2 +.....+(-1)^{n-1}a_{n-1}^2=\sum_{r=0}^{n-1}(-1)^{r-1}a_r^2 $$ in terms of $a_n$ and $n$. What I've done : I've tried replacing $x$ with $\frac{-1}{x}$ and then…
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Find the value of $ 99^{50}-\binom{99}{1}(98)^{50}+\binom{99}{2}(97)^{50}-\cdots \cdots +99$

Find the value of $\displaystyle 99^{50}-\binom{99}{1}(98)^{50}+\binom{99}{2}(97)^{50}-\cdots \cdots +99$ Binomial identity: $\displaystyle (1-x)^{99} = \binom{99}{0}-\binom{99}{1}x+\binom{99}{2}x^2-\cdots \cdots -\binom{99}{99}x^{99}$ I want be…
DXT
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proving $ \binom{n}{0}-\binom{n}{1}+\binom{n}{2}+\cdots \cdots +(-1)^{n-1}\binom{n}{m-1}=(-1)^{m-1}\binom{n-1}{m-1}$

proving $\displaystyle \binom{n}{0}-\binom{n}{1}+\binom{n}{2}+\cdots \cdots +(-1)^{\color{red}{m}-1}\binom{n}{m-1}=(-1)^{m-1}\binom{n-1}{m-1}.$ $\displaystyle \Rightarrow 1-n+\frac{n(n-1)}{2}+\cdots \cdots (-1)^{n-1}\frac{n.(n-1)\cdot…
DXT
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minimum value of sum of two number for which binomial coefficients is an even integer

for two non negative integer values of $r$ say $r_{1},r_{2}(r_{1}\neq r_{2})$ for which $\displaystyle \binom{1999}{r}$ is an even integer Then the minimum value of $r_{1}+r_{2}$ $\displaystyle \binom{1999}{r}$ represent coefficient of $x^r$ in…
DXT
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Coefficient of $x^5$ in $(1+x)^{21} + (1+x)^{22} + ... + (1+x)^{30}$

How do I find the coefficient of $x^5$ in the expansion of $(1+x)^{21} + (1+x)^{22} + ... + (1+x)^{30}$?
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Given that $\binom{n+1}{r-2}=28$, find $(n-7)!$

Is there a neat analytic way to solving a problem like this? If $\dbinom{n+1}{r-2}=28$, find the value of $(n-7)!$ Assume $n,r\in\mathbb{N}$ with $0\le r\le n+1$. An easy way to do it would be to memorize or construct Pascal's triangle to find out…
user170231
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What does "n over 1 without a line between" signify?

I'm starting to work my way through Algebra I by Jacobson after being out of college for 15 years, and he's using an expression I don't remember from college algebra. It's a number over a number without a line between. I assume it means "n divided…
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Trinomial Pascal's Triangle

I know that there's a trinomial theorem (and a multinomial theorem), but I was wondering if there was a similar structure for trinomials as there is for binomials, like Pascal's triangle. Thanks in advance!
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For all positive integer $n$ prove the equality: $\sum_{k=0}^{n-1}\frac{\binom{n-1}{k}^2}{k+1}=\frac{\binom{2n}{n}}{2n}$

For all positive integer $n$ prove the equality: $$\sum_{k=0}^{n-1}\frac{\binom{n-1}{k}^2}{k+1}=\frac{\binom{2n}{n}}{2n}$$ My work so far: $$\frac{n\binom{n-1}{k}}{k+1}=\frac{n(n-1)!}{(k+1)k!(n-k-1)!}=\frac{n!}{(k+1)!(n-k-1)!}=\binom{n}{k+1}$$
Roman83
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How to express $\binom{a+b}{n}$ as a sum of regular coefficients

I am trying to prove that $(1 + f(x))^a(1 + f(x))^b = (1 + f(x))^{a+b}$ in the world of formal power series. At a certain point in the prove I get \begin{align*} (1 + f(x))^a(1+f(x))^b& = \ldots \\ & = \lim\limits_{N \to \infty}…
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Solving a Binomial Expansion Question

I have a question which asks to find the coefficient of x and the constant term, for $f_n(x)$ given that $f_1(x) = (x - 2) ^ 2$ and $f_{n+1}(x) = (f_n(x) - 2) ^ 2, n >= 1$ Now I tried to derive the values like solving for $f_2$ and $f_3$ , but its…