Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

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Compute the value of a sum (as an expression involving one or two binomial coefficients)

I've been asked to compute the value of a sum. The answer should be an expression involving one or two binomial coefficients. The initial expression: $$ \sum_{k} \binom{80}{k} \binom{k+1}{31} $$ After many iterations, I think I'm still unable to…
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Show that for $n\geqslant1,\ \displaystyle \binom{2n}{n} = \dfrac{1\cdot3\cdot5\cdot\cdots\cdot(2n-1)}{2\cdot4\cdot6\cdot\cdots\cdot2n}2^{2n}$

Show that for $n\geqslant1,$ $$\displaystyle \binom{2n}{n} = \dfrac{1\cdot3\cdot5\cdot\cdots\cdot(2n-1)}{2\cdot4\cdot6\cdot\cdots\cdot2n}2^{2n}.$$ This is an exercise from the Preliminaries of David Burton's Elementary Number Theory. I started by…
user654528
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Binomial coefficient identity proof

I'm struggling with proving the identity $$\sum_{k=p}^{q}\binom{l}{m+k}\binom{s}{n+k}=\binom{l+s}{l-m+n}$$ where $$p=-\min(m,n)~ \text{and}~q=\min(l-m,s-q).$$ It reminds me of Vandermonde's identity but still I can't get it right. I would appreciate…
Nerwena
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Binomial coefficients with summation

$$\dfrac{\sum_{r=0}^{24} \binom{100}{4r}\binom{100}{4r+2}}{\sum_{r=1}^{25}\binom{200}{8r-6}}$$ The numerator is fine by multiplying 2 sequences we can easily get it but the denominator is taking a long time to be figured out using 8th roots of…
Alex
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Sum of multiplication of binomial with consecutive rising term

I am looking for a closed form for the following sum: $$\sum_{p=0}^{k} \left( \begin{matrix} n \\ p+1 \end{matrix} \right) \left( \begin{matrix} k \\ p \end{matrix} \right) 4^p = \;\;???$$ I have tried to expand: $$(1+2x)^n \cdot \left(…
CLic
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Calculate a sum of fraction of binomial coefficients

I am trying to calculate this fraction: $\sum_{n=1}^{101} \frac{100 \choose n-1}{103 \choose n}$. I wonder if there is some identity about binomial coefficient that would be helpful here.
Yang
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sum of coefficient of all even power of $x$

The sum of all Coefficient of even power of $x$ in $(1-x+x^2-x^3+\cdots +x^{2n})(1+x+x^2+x^3+\cdots +x^{2n}),n\in \mathbb{N}$ what i try for $n=1,$ we have $(1-x+x^2)(1+x+x^2)=(1+1)-(1)+(1+1)=3$ for $n=2,$ we…
jacky
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Transforming Binomialcoefficients

I don't understand the following equation which is presented in our lecture: $${p+q-1 \choose p-1} - { p+q-1 \choose p} = \frac{p-q}{p+q}{p+q \choose p},$$ where $p>q$ and $p,q \in \mathbb{Z}$. I have tried several manipulations of the…
Philipp
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value of $k$ in binomial sum

If $\displaystyle (1-x)^{\frac{1}{2}}=a_{0}+a_{1}x+a_{2}x^2+\cdots \cdots +\infty.$ and $a_{0}+a_{1}+a_{2}+\cdots+a_{10}=\frac{\binom{20}{10}}{k^{10}}.$ Then $k$ is what i…
jacky
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how can i prove this equation of binomial coefficients?

i dont know $-a$ in this equation really mean, explain it too please $$ \left(\begin{array}{c}a+m-1\\ m\end{array}\right) = (-1)^m \left(\begin{array}{c}-a\\ m\end{array}\right) $$
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Non-trivial alternating sums of binomial coefficients

Consider a binary vector $a_0, a_1,\,\dots\,, a_n$ and an equation $$\sum_{i=0}^n a_i \cdot (-1)^i {n \choose i} = 0.$$ You can satisfy this trivially when 1) all $a_i$ are 0, or 2) all $a_i$ are 1, or 3) $n$ is odd and $a$ satisfies $a_i = a_{n-i}$…
Michal
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Prove $\sum_{i=0}^{\min(x,y)}\binom{x}{i}\binom{y}{i}2^{x+y-(i+1)}=\sum_{i=0}^{\min(x,y)}2^{x+y-(i+1)} (-1)^i \frac{(x+y-i)!}{(x-i)!(y-i)!i!}$

I found the formula below counting the path on the grid (link). $$\sum_{i=0}^{\min(x,y)}\binom{x}{i}\binom{y}{i}2^{x+y-(i+1)}=\sum_{i=0}^{\min(x,y)}2^{x+y-(i+1)} (-1)^i \frac{(x+y-i)!}{(x-i)!(y-i)!i!}$$ How to prove this (I prefer more intuitive…
ueir
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Prove that the sum in each row of a Pascal triangle is double that of the previous row

I'm trying to prove that the sum of every row in Pascal triangle is double the previous row by using Pascal's rule: $${n \choose k} = {n-1 \choose k} + {n-1 \choose k-1}.$$ It's easy for me to understand why is it correct. We can use the rule in…
Bob_Bobb
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What is the sum of the second numbers in the first $100$ rows of Pascal's triangle (excluding the first row)?

What is the sum of the second numbers in the first $100$ rows of Pascal's triangle (excluding the first row, the row containing a single $1$)? The sum should be from the second to the hundredth row. Starting from the second row, I initially…
a23
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how to calculate $\sum^{n}_{k=m}\binom{k}{m}\binom{n}{k}$?

For natural numbers $m \leq n$ calculate (i.e. express by a simple formula not containing a sum) $$\sum^{n}_{k=m}\binom{k}{m}\binom{n}{k}.$$ I searched and answer is…