Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
1
vote
1 answer

Why is it not possible to calculate the amount of combinations for a byte using the Binomial coefficient

I'm trying to understand the Binomial coefficient. I found this source which gives clear information: https://www.calculatorsoup.com/calculators/discretemathematics/combinations.php After reading, I was wondering if I could use the Binomial…
Julian
  • 113
1
vote
2 answers

Binomial theorem, prove an expression

Forgive me guys, i don't really know how to edit this so it would look like 'maths' but i really don't understand what this is asking me to do -_- Use the Binomial Theorem to show that: $$ 0 = \sum_{0 \le k \le n} \binom{n}{k} (-1)^k $$
1
vote
2 answers

proving complex Binomial Identity

Proving the result $\displaystyle \sum^{\infty}_{n=0}\binom{2n}{n}x^n=\frac{1}{\sqrt{1-4x}}$ what i try $\displaystyle (1+x)^{n}=\sum^{n}_{r=0}\binom{n}{r}x^r$ $\displaystyle (x+1)^n=\sum^{n}_{r=0}\binom{n}{n-r}x^{n-r}$ Campare coefficient of $x^n$…
jacky
  • 5,194
1
vote
1 answer

Problem with binomial expansion

So here is the problem: Find the constant term in the expansion of (x-(2/x))^2 ·(x^2 +(2/x))^3 I understand I can just use my calculator to figure out the answer, but is there any simple way to solve that ? Thanks!
busyyyy
  • 195
1
vote
1 answer

remainder in double sum having binomial coefficients

find the remainder when $\displaystyle \sum^{2014}_{r=0}\sum^{r}_{k=0}(-1)^k(k+1)(k+2)\binom{2019}{r-k}$ is divided by $64$ what i…
jacky
  • 5,194
1
vote
5 answers

Find the coefficient of x in the expansion of $(2x^2+x-3)^8$.

This is a question from IB past papers. I factorized the equation to (2x+3)(x-1) and I tried finding the coefficients, but I got a wrong answer. Maybe I have forgotten how to solve it. Can someone tell me the way to solve it, but not the whole…
1
vote
1 answer

the value of $\sum^{3m}_{r=0}(-1)^r\binom{6m}{2r}$ is

the value of $\displaystyle \sum^{3m}_{r=0}(-1)^r\binom{6m}{2r}$ is what i try opening sum $$\binom{6m}{0}-\binom{6m}{2}+\binom{6m}{4}-\binom{6m}{6}+\cdots +(-1)^{3m}\binom{6m}{6m}$$ $$(1+x)^{6m}=\binom{6m}{0}+\binom{6m}{1}x+\binom{6m}{2}x^2+\cdots…
jacky
  • 5,194
1
vote
1 answer

natural number values of $(x,y)$ in binomial coefficients

Find natural number $(x,y)$ in $\displaystyle \frac{x!}{y!(x-y)!}=2019$ what i try $\displaystyle \frac{x!}{y!(x-y)!}=2019=3\cdot 673$ pairs are $(2019,1),(2019,2018)$ How to find other natural values of $(x,y)$ help me please
jacky
  • 5,194
1
vote
2 answers

sum of $\sum^{n}_{k=0}(-1)^k\cdot \frac{\binom{n}{k}}{\binom{k+3}{k}}$

Finding sum of $\displaystyle \sum^{n}_{k=0}(-1)^k\cdot \frac{\binom{n}{k}}{\binom{k+3}{k}}$ Try: Using $$\int^{1}_{0}x^m\cdot (1-x)^ndx = \frac{m!\cdot n!}{(m+n+1)!}=\frac{1}{(m+n+1)\binom{m+n}{n}}.$$ So $$…
DXT
  • 11,241
1
vote
2 answers

Proving that $\sum_{k=0}^n{(-1)^k\over k+1}\binom{n}{k}={1\over n+1}$

I would like if possible to have a proof of yet another theorem of Binomial Coefficients. This time it is $$\sum_{k=0}^n{(-1)^k\over k+1}\binom{n}{k}={1\over n+1}$$ This arises in a proof of the theorem to the effect that…
1
vote
1 answer

Limiting sum of binomial coefficients multiplied by powers

I want to prove that: $$\lim_{n \rightarrow \infty} \sum_{k=1}^m {m \choose k} \Big( \frac{k}{m} \Big)^n = 1.$$ My progress so far: Define the function $F(x) \equiv (1+x)^m$ and the operator $\tilde{\nabla} \equiv x \cdot \frac{d}{dx}$. Using the…
Ben
  • 4,079
1
vote
1 answer

Show that there are $\binom{n-1}{k-1}$ ways to describe $n$ as a sum with $k$ positive, ordered parts

Show that there are $\binom{n-1}{k-1}$ ways to describe $n$ as a sum of $k$ positive, ordered parts. I know that there are $n-k+1$ options for the first part of the sum. And the first choice affects the choice for the snd part and so on. I have…
RM777
  • 987
1
vote
2 answers

Coefficient of terms in expansions

Can we have general method to find coefficient of $x^ k$ in exapansion of $(1+x+x^2)^n$? like if it is k=3,4 or something like that we can use multinomial expansions and solve but when lets say k is n , using multinomial to solve gives sets of…
maveric
  • 2,168
1
vote
1 answer

How can I find the Coefficent of a term when I am multiplying two binomial expansions?

For Example, what is the coeffecint of $x^{-1}$ in the expansion of $$ (\frac{1}{2x}+3x)^5​(x+​1)^4\text{?} $$ How can I find the coefficient without expanding by hand?
1
vote
2 answers

Binomial Expansion coefficients

Find the coefficient of $x^3 y^4$ in the expansion of $(2x-4y)^7$. I would also like an explanation for how the final answer was obtained.