Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
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Is there any way to expand this using the binomial theorem?

$(h-2.5i)^{1/2}$ I'm trying to isolate i, is it possible? Cheers! EDIT: $i$ is NOT $\sqrt{-1}$, it's just a variable and $h$ is a constant. EDIT2: It's in sigma notation like so: $$\sum_{i=1}^{14}(h-2.5i)^{1/2}$$
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How do we express binomial coefficients as linear expressions?

I have a question from Putnam and Beyond. It says that "...for some positive integers m and k, the binomial coefficient $m \choose k$ is a linear combination of $m^k$, $m \choose {k−1}$ , $\dots$ , $m\choose 0$ whose coefficients do not depend on…
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Order of the maximum term of (a +b)^(-m)

I would like, if possible, to obtain a proof of the theorem below. "Being given real numbers a and b, with |a|>|b|, and m is a positive integer, the order p, which occupies the maximum term (in absolute value) the development of power (a+b)^(-m) ,…
Paulo Argolo
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Binomial Expression

Please give me feedback on my answer to this question. Question: For all $ n\geq1:\binom{2n}{0}+\binom{2n}{2}+\binom{2n}{4}+\cdots+\binom{2n}{2k}+\cdots+\binom{2n}{2n} $ is equal to $…
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Binomial expansion question. easy!

I'm trying to do the binomial expansion of $(x-2)^{1/2}$. How do you do it? As far as I'm aware the expansion only works for $(1+x)^n$. How could I get it in that form? Thanks.
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Question about Binomial Distribution

The chance of a rose flower blooming is $.28$. You are going to plant $5$ rose flowers, what are the chances of $4$ of them blooming? I was thinking the answer would be $35$% since $28\%*5=140$ and $\frac{140}{4}=35$. Is this correct?
Lil
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Binomial coefficients in series

Here's a tricky one which I don't know how to start so any help would be appreciated. Show that no 4 consecutive binomial coefficients can be in AP and no 3 consecutive binomial coefficients can be in GP or HP Is there a general method to be…
user34304
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Cumulative Binomial Distribution function , Solve for n (trials)

how can one solve for $n$ in the Cumulative Binomial Distribution Function $P=\sum_{i=0}^{i=c-1} {n \choose i} p^{i}(1-p)^{n-i}$. thanks in advance, D.
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Probability binomial distribution and Poisson distribution

It is found that 5% of screws in a factory are found to be defective. Use the Poisson theorum and the binomial theorum to compute the probability that two or more are found to be defective if a sample of 20 screws is tested. Can anyone pleasssssse…
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Binomial Coefficients-Squares

A discrete random variable $X$ takes value $0,1,2, \ldots n$ with frequency $\binom{n}{0}, \binom{n}{1}, \ldots, \binom{n}{n}$. Find the variance. I have calculated the mean as such $$\mathbb{P}(X)=…
kangkan
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Finding coefficient of $x^k$ in summation of binomial series

I am not able to solve this problem Find the coefficient of $x^k\;\;(k$ is greater than or equal to zero and lesser than or equal to $n$) in the expansion of $E = 1 + (1+x) + (1+x)^2 .... + (1+x)^n$ The final simplified answer is $(n+1)C(k+1)$ Any…
user34304
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appling the binomial theorem

When trying to apply the binomial theorem to a problem, I found a solution that involves this line: $(x+1)(x^2-2)^9 = \sum_{k=0}^9 { 9 \choose k } (-1)^{k-1}2^{9-k}(x^{2k}+2^{2k + 1})$ I know the binomial theorem and the formula: $\sum_{k=0}^n {n…
iveqy
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Prove: $\binom{n}{r-1} + 2\binom{n}{r} + \binom{n}{r+1} = \binom{n+2}{r+1}$

Prove: $\binom{n}{r-1} + 2\binom{n}{r} + \binom{n}{r+1} = \binom{n+2}{r+1}$ This was one of the questions that my professor gave me as extra practise however I want to know a more efficient way of getting to the answer as my method was very…
Pauly
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Prove equality (binomial-coefficients)

$$\sum_{i=k}^{n-l} {i \choose k}{n-i \choose l} = {n+1 \choose k+l+1}$$ I understand how to prove this using that equality: $$\sum_{i=k}^{n-l} {i \choose k}{n-i \choose l} = {n \choose k+l} + \sum_{i=k}^{n-l-1} {i \choose k}{n-i-1 \choose l }$$ But…
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Binomial identity with a parameter L.

This identity arose during my attempts to disprove the existence of integer loops in the Collatz Conjecture. Is there a name for it? It contains a selectable parameter, $L \geq 1.$ I remember seeing the factor (n-k+1) somewhere. $L\geq 1, \ n\geq…