Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

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How can you derermine if you are allowed to use use 0^0=1 in this proof?

There is a chapter in my math book about pascals triangle. In one of the problems you are supposed to prove that: $$\sum_{i=0}^n \binom{n}{i} = 2^n$$ where $n$ and $i$ are natural numbers. My first instinct was to just use the binomial…
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Question about the binomial coefficent why is ${1} \choose {i-1}$ $=0$ if and only if $i-1>1$?

I've come across a statement that says we have ${1} \choose {i-1}$$=0$ if and only if $i-1>1$. I don't know how to interpret the binomial coefficient when the bottom term is greater than the top. Why does this hold?
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Binomial coefficients relationship to combinations

Consider the expansion of $(a+b)^9$. The coefficient of the term $a^7b^2$ is the number of ways to select $7$ a's from the $9$ factors of $a+b$. Why is this the case? Furthermore, this seems like an intuitive proof of why binomial coefficients are…
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Coefficients of $(1+x)^n$ and $(1-x)^n$ for $n \in \mathbb{R}.$

I read somewhere that the coefficient of $(1+x)^n$ is $1 + nx + \frac{n(n-1)}{2!}x^2 + \cdots.$ For $n=-\frac{1}{2},$ the denominator becomes $2^n \cdot n!,$ while the numerator becomes $1 \cdot 3 \cdot \dots \cdot (2n-1) = \frac{(2n!)}{2^n \cdot…
Mike Smith
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Pascals triangle and binomial theory $(1+x)^n$ expansion

I have a question that I can solve quite nicely with the binomial theorem; however, I am required to use pascals triangle for a lower level course: In the expansion of $(1+x)^n$ the first three terms are $1$, $-18$, and $144$. Determine the values…
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what is the reciprocal inner product of lower triangle Pascal matrix?

Each row of the Lower triangle matrix $L$ contains the binomial coefficient padded with zero. $L_{i,j} = {i \choose j}$. Define the reciprocal inner product of $\frac{\vec{v}}{\vec{w}}$ where $\vec{v}, \vec{w} \in \mathbb{R}^n$ as $\sum_{i=0}^{n-1}…
peng yu
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Why will there always be this term in $(x+h)^n$?

I am trying to understand why the expression $(x+h)^n$ will always have a term $n\times h\times x^{n-1}$ in this proof for the power rule and am not understanding what the proof in the image below means when it says 'take $x$ from all but one factor…
Princess Mia
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Variation of the binomial coefficient function

If we define ${n \choose k}_m := \frac{n(n-m)(n-2m)...(n-(k-1)m)}{k!}$, then it can be shown that this is an integer value for all integer values of $n,k,m$. Does this function have a name? If ${n \choose k}$ counts the number of ways to choose $n$…
Feryll
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Equation with binomial coefficient (coefficients are fractional)

I am trying to solve/approximate $x$ in the following equation: $$\binom{x\cdot \log_2n}{\frac{x\cdot \log_2n}{2}} = n,$$ where $n$ is a natural number. Obviously $x$ is a decreasing function of $n$ and for $n=2$, $x=2$. But besides that and some…
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Help finding a proof of an identity $\sum_{k=1}^n(-1)^{n-k}{n \choose k}{n+k \choose k-1}=n$

Help finding a proof of an identity $\sum_{k=1}^n(-1)^{n-k}{n \choose k}{n+k \choose k-1}=n$. I have checked that the equality holds for n = 2,3,4,5,... etc. However I have no idea how to prove this identity for arbitrary n.
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How to use binomial theorem

How to use binomial theorem,From (1) to get…
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Pascals identity when k=n

Pascal's identity states that $\binom{n}{k}$ = $\binom{n-1}{k-1}$ + $\binom{n}{k+1}$ However, if we let k = n then according to the identity we have that $\binom{n-1}{n-1}$ + $\binom{n}{n+1}$ which is then undefined if I am correct. So must n>k for…
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Simplifying $(x-1)\cdot(x-3)\cdots (x-(n-2))$ in terms of binomial coefficients.

Can we write the following product in terms of binomial coefficients ? $(x-1)\cdot(x-3)\cdots (x-(n-2))$. i.e the the product take up odd numbers.
wkmath
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Finding the highest power of $2$ that divides $\sum_{1}^{1024}\binom{1024}{k}2^k$

If $S=\sum_{1}^{1024}\binom{1024}{k}2^k$, find highest power of $2$ dividing $S$. I have tried solving using the fact that its equal to $$2^{11} + 2^{2} \binom{1024}{2} + \cdots + 2^{1024}$$ taking $2^{11}$ common we get number to be of form…
Orion_Pax
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Simplifying Expression of a Binomial Coefficient from Knuth (1.2.6) Example 2

Knuth (Section 1.2.6) in Example 2 asks What is the value of $\sum_{k} \binom{n+k}{2k}\binom{2k}{k} \frac{(-1)^k}{k+1}$, if $n$ is a non-negative integer? Knuth references how to simplify products with Equation (20) $$\binom{r}{m} \binom{m}{k} =…
Tyler
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