Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

7695 questions
0
votes
8 answers

Find constant term in the expansion of $\left (1+\frac x2 -\frac 2x \right)^4$

Finding the constant term for $$\left (1+\frac x2 -\frac 2x \right)^4$$ is easy, but that would require converting the expression into a binomial. However, I have no idea about how to do that. Completing squares doesn’t work because we have a…
Aditya
  • 6,191
0
votes
1 answer

How to find coefficient of $s^{12}t^{13}$ in the expansion of $(2s-3t)^{25}$

I am trying to find the coefficient of $s^{12}t^{13}$ in the expansion of $(2s-3t)^{25}$. I don't know if I am doing right, but I know we have to start with $\binom{25}{12}$. When $t^{13}$ is added, becomes more confusing. Any help in handling this…
0
votes
1 answer

Why does this binomial coefficient develop like this?

This is the question. Suppose a column has $m$ $1$’s and therefore $n − m$ $0$’s, and we randomly choose $k$ rows to consider when computing the minhash. Prove that the probability of getting “don’t know” as the minhash value for this column is at…
SeHoon
  • 1
0
votes
3 answers

Binomial coefficients with sums $\sum_{i=0}^ni^2{n\choose i} $

I need help solvinf this task, if anyone had a similar problrm it would help me. The task is: Calculate : $\sum_{i=0}^ni^2{n\choose i} $ I tried this: $ \sum_{i=0}^ni^2{n\choose i}\\ \sum_{i=0}^ni^2\frac{n!}{i!(n-i)!}\\…
LogicNotFound
  • 465
  • 2
  • 6
0
votes
2 answers

show that ${n \choose 0} - {n \choose 1} + \cdots + (-1)^n {n \choose n} = 0$

I was asked to show that this formula is true. ${n \choose 0} - {n \choose 1} + \cdots + (-1)^n {n \choose n} = 0$ I've already proven that ${n \choose 0} + {n \choose 1} + \cdots + {n \choose n} = 2^n$ However, I'm not really sure if these two are…
23408924
  • 505
  • 3
  • 14
0
votes
0 answers

Binomial coefficient --sums

I need help solving this task, if anyone have similar problem, it would help me. $\sum\limits_{i=0}^{673} \binom{2019}{3i}$ More precisely I don't know how to start at all, any help is welcome. Thanks in advance !
LogicNotFound
  • 465
  • 2
  • 6
0
votes
1 answer

Help with a question on binomial

Prove that $$\sum_{r=1}^{k}(-3)^{r-1}\dbinom{3n}{2r-1}= 0,$$ where $k=\frac{3n}{2}$, and $n$ is an even positive integer
Manoj
  • 1,757
0
votes
3 answers

Find the coefficient of $x^{24}$ in the binomial equation

Find the coefficient of $x^{24}$ in the equation ${\left( {1 - x} \right)^{ - 1}}.{\left( {1 - {x^2}} \right)^{ - 1}}.{\left( {1 - {x^3}} \right)^{ - 1}}$ My approach is as follow The equation used is ${\left( {1 - x} \right)^{ - n}} =…
0
votes
0 answers

Binomial coefficient (case differentiation)

If you want to proof $\binom{n}{k}$ + $\binom{n}{k+1}$ = $\binom{n+1}{k+1}$, you have to differentiate between 5 cases. Why 5 cases and where do they come from ? It should have something to do with $\binom{N}{k}$ = $\frac{n!}{k!(n-k)!}$ .
Seenes
  • 87
0
votes
0 answers

What is the approximation ratio between $n \choose k$ and $(n/k\cdot e)^k$

My teamwork claimed that a good approximation for $n \choose k$ is $(\frac{n}{k}\cdot e)^k$. he said to me that in most cases $n \choose k$ is really closed to $(\frac{n}{k}\cdot e)^k$ (up to factor of 1.25). What is the worst case approximation…
0
votes
1 answer

Binomial coefficient expansion question

I'm trying to follow this expansion (linked below) for one of my classes, but nothing I have tried is proving successful. Any hints or help would be very appreciated. Thanks :) Binomial coefficient expansion
0
votes
1 answer

Calculating binomial coefficient

I am familiar with: $$ \binom{n}{k} = \frac{n!}{k!(n-k)!} $$ Now, i have an excercise in calculus which gets to the point that we should calculate: $$ \frac{\binom{3n+1}{n+1}}{\binom{3n}{n}} $$ The answer says that:…
Alon
  • 1,647
0
votes
1 answer

Binomial coefficient: Calculate and save in the simplest possible form:

I found a solution for (c) here on this platform but I'm not sure how to solve rest of the problems because a negative number and a fraction in this situation is a novelty for me which I currently don't know how to deal with. Can somebody help me…
0
votes
1 answer

General relation in binomial expansion

If $3$rd, $4$th, $5$th and $6$th terms in the expansion of $(x + a)^n$ be respectively $a$, $b$, $c$ and $d$ then: $\frac{b^2 - ac}{c^2 - bd}$ = $\frac{5a}{3c}$. Similarly, If $6$th, $7$th, $8$th and $9$th terms in the expansion of $(x + a)^n$ be…
Nimit
  • 496
0
votes
2 answers

The term independent of $x$ in the expansion

What is he term independent of $x$ in the expansion of $$ \Bigg[\left(\dfrac{x+1 }{ x^{2/3} - x^{1/3} + 1}\right ) - \left(\dfrac{x - 1 }{ x-x^{1/2}}\right)\Bigg]^{10} $$