Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

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Show that $\dbinom{2n}{n} + \dbinom{2n}{n-1} = \frac{1}{2} \dbinom{2n+2}{n+1}$

Show that $\dbinom{2n}{n} + \dbinom{2n}{n-1} = \frac{1}{2} \dbinom{2n+2}{n+1}$ By induction, suppose that for some n its true, $\dbinom{2n}{n} + \dbinom{2n}{n-1} = \dbinom{2n+2}{n+1}$ by theorem, but, I don't know how to prove that …
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How to find all the binomial coefficients for the given equation?

Given the equation $$x(x-1)(x-2)(x-3)(x-4)\ldots(x-100),$$ how can I efficiently calculate the coefficients of $x^1,x^2,x^3,\ldots$ without actually multiplying the terms?
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Binomial coefficients sum problem

I am trying to answer the following problem but I barely understand the question and I've no idea how to proceed. Calculate the value of $\sum\limits_{k = 0}^n 5^k\binom nk$ for cases where $n = 1,\;2,\;3$. Could somebody please give me some…
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Binomial coefficient identity ${n \choose 2} + n = {n + 1 \choose 2}$

I can see why this is true using Pascal's triangle or the recurrence relation, but algebraically there must be a way and I'm just missing something (trying to sort out factorials using the binomial coefficient formula didn't work out for me). ${n…
tau
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How can I prove this equation is correct?

$$ \left(\begin{array}{c}a+b\\ n\end{array}\right) = \sum_{i=0}^n \left(\begin{array}{c}a\\ k\end{array}\right) \left(\begin{array}{c}b\\ n-k\end{array}\right)$$
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Value of expression $\sum\limits^{10}_{r=2}\binom{r}{2}\cdot \binom{10}{r}$

The value of expression $\displaystyle \sum\limits^{10}_{r=2}\binom{r}{2}\cdot \binom{10}{r}=$ What I tried: $$\sum^{10}_{r=2}\frac{r!}{2!\cdot (r-2)!}\times \frac{10!}{r!\cdot (10-r)!}$$ $$\frac{10!}{2!}\sum^{10}_{r=2}\frac{1}{(r-2)!\times…
jacky
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can we have $(\partial _x+f(x))^n=\partial _x^n+\binom{n}{1} (\partial _x)^{n-1}f(x)+\cdots+(f(x))^n$?

We know that $(a+b)^n=a^n+\binom{n}{1}a^{n-1}b+\cdots+b^n$ when $a,b$ commutes to each other. Am I right? My question is- Can we expand $(\partial _x+f(x))^np(x)$ or $(\partial _x+f(x))^n$ in the above formula ? i.e., can we have $(\partial…
MAS
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When do we have $(a-b)^n=(a+b)^{-n}$?

Here, $a, b$ are positive reals, and $n$ is a positive integer. It seems that the binomial theorem for negative exponents gives some solutions. But what is the exact condition for the parameters.
Zoran
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$\sum_{k=0}^n \sum_{l=0}^k \binom{n}{k} \binom{k}{l} (-1)^{k-l} s_l ?= \sum_{l=0}^n \sum_{k=l}^n (-1)^{n-k} \binom{n}{k}\binom{k}{l}s_l $

I want to prove \begin{align} \sum_{k=0}^n \sum_{l=0}^k \binom{n}{k} \binom{k}{l} (-1)^{k-l} s_l ?= \sum_{l=0}^n \sum_{k=l}^n (-1)^{k-l} \binom{n}{k}\binom{k}{l}s_l = s_n \end{align} I can understand the last step using…
phy_math
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Applying Stirling's formula to natural logarithm of binomial coefficient

Suppose we have the Hilbert entropy function with $0\leq\lambda\leq\frac{1}{2}$ $$H(\lambda) = \lambda \ln{\frac{1}{\lambda}+(1-\lambda)\ln{\frac{1}{1- \lambda}}}.$$ I would like to show using Stirling's formula applied to the natural…
Tony_V
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Fraction with binomial coefficient

I want to prove, that $\binom{a/m}{k}$, $a \in \mathbb{Z}, k \in \mathbb{N}, m \in \mathbb{N}_{\geq 1}$, can be rewritten as $\frac{b}{m^n}$ with $b \in \mathbb{Z}, n \in \mathbb{N}$. I thought of proving it by induction but failed at transforming…
Tim
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How to find $a$ and $n$ in the following equation $(1+ax)^n$ by using Pascal triangle?

I have the following equation: $(1+ax)^n$ for which the first three terms are $1+24x+240 x^2$. I found the coefficients to be $a=4$ and $n=6$ by using the binomial expansion but can I do it by using the Pascal triangle?
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Solving binomial expansions given some information about the coefficients of x.

I have the following question that I'm trying to work out an answer to: "In the binomial expansion of $(1+x)^n$ where $n >= 4$, the coefficient of $x^4$ is $3/2$ times the sum of the coefficients of $x^2$ and $x^3$. I have already figured it out in…
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Find $\sum_{k = 0}^{11} \frac{1}{k+1}\binom{11}{k}$

How could I solve this sum using properties from Pascal's Triangle and Pascal's rule? $$ S = \frac{\binom{11}{0}}{1} + \frac{\binom{11}{1}}{2} + \frac{\binom{11}{2}}{3} + \ldots + \frac{\binom{11}{11}}{12}. $$
Daniel Sehn Colao
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Are there ‘product expressions’ for sequences of binomial coefficients similar to the ‘product expression’ for the central binomial coefficients?

If we want a central binomial coefficient, for n greater than zero we have a ‘nice’ expression $${2n \choose n} =\prod_{k=1}^{n}{(4-\frac{2}{k})}$$ which is term-wise rational and produces each binomial coefficient matching ${2n \choose n}$ along…
tuespetre
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