Questions tagged [binomial-coefficients]

For questions involving the coefficients involved in the binomial theorem. $ \binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

The binomial coefficient $\binom{n}{k}$ can be defined in several equivalent ways for $n$ and $k$ non-negative integers:

  1. The number of subsets of size $k$ of a set of size $n$.
  2. Element $k$ of row $n$ in Pascal's triangle (counting the first element or row as $0$).
  3. $\dfrac{n!}{k!(n-k)!}$
  4. The coefficient of $x^k$ in $(1+x)^n$.

The binomial theorem says that $$(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$$ using the convention that $0^0=1$.

Binomial coefficients can be extended for arbitrary complex $\alpha$ through the formula: $$\binom{\alpha}{k}=\frac{\alpha(\alpha-1)(\alpha-2)\dots(\alpha-k+1)}{k(k-1)(k-2)\dots1}$$

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Are there four consecutive binomial coefficients in a row in an arithmetic progression?

Are there four consecutive binomial coefficients in a row in an arithmetic progression? This is suggested by Will Jagy's comment to this question: Find $n$ and $k$ if $\:\binom{n\:}{k-1}=2002\:\:\:\binom{n\:}{k}=3003\:\:$ Here is my answer: No. (If…
marty cohen
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Problem with binomial coefficients and their symmetry

I'm going through my workbook and ran across this: $$\sum_{k=0}^{n-1}\binom{4n}{4k+1}=\frac{1}{2}\sum_{k=0}^{n-1}\binom{4n}{4k+1}+\frac{1}{2}\sum_{k=0}^{n-1}\binom{4n}{4(n-k-1)-1}$$ $$=\frac{1}{2}\sum_{k=0}^{2n-1}\binom{4n}{2k+1}$$ The first thing…
A6SE
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Binomial Theorem Expansion With Inverse Variable?

I need to find the 6th term of $(4x-\frac{1}{2x})^{10}$ To my knowledge, the 6th term would be: $\binom{10}{6}$$(4x)^6$$(-\frac{1}{2x})^{4}$ = 210*4096$x^6$$(\frac{1}{16x^4})$ = 53760$x^2$...but the answer is -8064. What went wrong?
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Can't understand step in proof of Lucas's Theorem

I am having trouble understanding why the "Hence $p$ divides . . . " part follows. This is from the Wiki article on Lucas's Theorem. Help appreciated! If $p$ is a prime and $n$ is an integer with $1≤n≤p-1$, then the numerator of the binomial…
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Binomial expansion and factorials

I have come across this question, the answer is simply stated as 36, and while I can see how 36 is gotten, I don't understand why? How is it meant to be known that b = 36, just looking at the formula is nice and quick but I much prefer to…
Jonathan.
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Write $1001$ as a binomial coefficient $\binom n k$ with $n ≤ 20$

I have this question involving the binomial theorem and have the answer but trying to understand properly how to get there. In the solutions the first step in the solution is to write $1001 = 7\cdot 11\cdot 13$ and therefore $n\ge 13$,this is what I…
rb20
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Find the coefficient of $x^3$ in the expansion of $(1+x)^3(2+x^2)^{10}$

The coefficient of $x^3$ in the expansion of $(1+x)^3(2+x^2)^{10}$ is (A) $2^{14}$ (B) $31$ (C) $3\choose{3}$ $+$ $10\choose{1}$ (D) $3\choose{3}$ $+2$$10\choose{1}$ (E)$3\choose{3}$$10\choose{1}$$2^9$ The answer is (A), although I wasn't able to…
Poko
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How can I solve for N in the inequality below?

I know that the answer is N = 537, but I'm not sure how to solve for N analytically. More precisely, my question is how can I simplify the sum of the binomial coefficients ? The inequality is at this link:…
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Binomial coefficient, adding further 'combinations'

As a programmer, discovering the binomial theorem has helped me with alot. I want to solve something using maths as source and I wonder if you can help me define this one: Regarding this question and its following outcome with: $${20 \choose 10} =…
OHMR
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Recursive formula for an inverted binomial table

This is an inverted binomial table: $$ \begin{array}{ccccccccccc} &&&&&&1&&&&&&\\ &&&&&1&&1&&&&&\\ &&&&2&&1&&2&&&&\\ &&&6&&2&&2&&6&&\\ &&24&&6&&4&&6&&24&&\\ &120&&24&&12&&12&&24&&120\\ 720&&120&&48&&36&&48&&120&&720 \end{array} $$ Each element…
JMP
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Lower bound for binomial coefficient

Prove that for sufficiently large $ n $ the following inequality holds: $ \binom{5n}{4n}>12^n $. Thank you in advance.
virnoy
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Please help with finding binomial coefficient in the following expression

I'm trying to find the coefficient of $x^{2m}$ from the both sides of the following equality: $$ \frac{(1-x^2)^n}{(1-x)^n} = (1+x)^n $$ For the right side of equality I've found it as follow: $$ [x^{2m}] (1+x)^n=\binom{n}{2m} $$ With the left side…
Mike
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Probability and Statictic / Binomial

The cost of a trial conducted in the research and development center of an industrial establishment is known to be 1 million dolars. If the test is negative, in addition to this a new trial is required, which would cost additional 300 thousand…
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Simple Question About Binomial Theorem

On one of my calculus lectures I've seen the lecturer write: $$(1+p)^n=1+np+\frac{n(n-1)}{2}p^2+\cdots+p^n$$ Could you please explain to me how did he get this equation? Thank you very much.
Anonymous
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$\big(1+\frac {C_0}{C_1}\big) \big(1+\frac {C_1}{C_2} \big) \cdots \big(1+\frac {C_{n-1}}{C_n} \big) =?$

If $(1+x)^n =~~ ^nC_0 ~+~ ^nC_1~x ~+~ ^nC_2 x^2~+~\cdots+~ ^nC_n x^n $, then the value of : $$\bigg(1+\dfrac {C_0}{C_1}\bigg) \bigg(1+\dfrac {C_1}{C_2} \bigg) \cdots \bigg(1+\dfrac {C_{n-1}}{C_n} \bigg)$$ is =? Attempt: I have been…
MathMan
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