Questions tagged [cardinals]

This tag is for questions about cardinals and related topics such as cardinal arithmetics, regular cardinals and cofinality. Do not confuse with [large-cardinals] which is a technical concept about strong axioms of infinity.

Cardinality is a notion of size for sets, usually denoted by $|A|$ as the "cardinality of $A$". With finite sets the cardinality is simply the number of elements which are members of a set.

Dealing with infinite sets we can measure them in different ways. Cardinal numbers are very natural in the sense that they do not require extra structure (such as relations and operations defined on the set to be preserved).

In formal terms, suppose $f\colon A\to B$ (i.e. $f$ is a function whose domain is $A$ and its range is a subset of $B$).

We say that $f$ is injective if $f(a)=f(b)$ implies $a=b$; we say $f$ is surjective if its range is all $B$, namely for any $b\in B$ there is $a\in A$ such that $f(a)=b$.

If $f$ is both surjective and injective we say that $f$ is a bijection from $A$ to $B$. The inverse of a bijection is also a bijection.

Now we can define an equivalence relation on sets, $A\sim B$ if and only if there is some $f\colon A\to B$ which is a bijection.

Assuming the Axiom of Choice, we have that every set can be well ordered, and therefore there is a least ordinal which is equivalent to $A$, so we can assign it as a canonical representative for the equivalence class, usually denoted by $\aleph_\alpha$ where $\alpha$ is an ordinal, or as general Greek letters such as $\kappa,\lambda$.

Before defining the $\aleph$ numbers we need to define initial ordinals. Let $\alpha$ be an ordinal, if there is no $\beta<\alpha$ and $f\colon\alpha\to\beta$ which is a bijection, then $\alpha$ is called an initial ordinal.

The $\aleph$ numbers are defined by transfinite induction as:

  1. $\aleph_0 = |\omega| = \omega$ (note that $\omega$ is an initial ordinal),
  2. $\aleph_{\alpha+1} = \aleph_\alpha^+$ (where the $\cdot^+$ means the smallest initial ordinal above the one defined for $\aleph_\alpha$)
  3. If $\beta$ is a limit ordinal, then $\displaystyle\aleph_\beta = \bigcup_{\delta<\beta}\aleph_\delta$ (It is easy to verify that the union of initial ordinals is an initial ordinal).

The confinality of an $\aleph$ number is the minimal cardinality of a set which is unbounded in the initial ordinal matching the $\aleph$ number.

A cardinal is called regular if its cofinality is itself, otherwise it is called singular.

Example: $\aleph_0$ is regular, because for a set to be unbounded below $\omega$ it cannot be finite.

$\aleph_1$ is also regular, every ordinal below $\omega_1$ is countable, and the union of countably many countable ordinals is just countable - which is still below $\aleph_1$.

Example: $\aleph_\omega$ is singular, recall $\displaystyle\aleph_\omega=\bigcup_{n<\omega}\aleph_n$. Therefore the set $\{\omega_n\mid n<\omega\}$ (the collection of initial ordinals whose cardinality is less than $\aleph_\omega$) is unbounded, and its cardinality is merely countable.

The question whether or not there exists $\aleph_\delta$ such that $\delta$ is a limit ordinal, but $\aleph_\delta$ is regular is unprovable in ZFC. It is known that it is consistent that there are none, but unknown that it is inconsistent that there are. Cardinals with this property are called Large cardinals and are used for consistency proofs.


In the absence of choice we can no longer have canonical representatives for the equivalence classes, and things become tricky. The class of cardinals can still be defined, however in a slightly different way - usually Scott's trick.

However, to show how things can break down it is consistent with ZF that there is no choice function on the equivalence classes (i.e. you cannot have canonical representatives).

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The cardinality of the set

Let $\mathbb{G} =\{ a^b + \sqrt{c}: a,b,c\in \mathbb Q \}$ I guess the set $\mathbb{G}$ is countable set, but I can't show it properly. How to start the proof?
J.Exactor
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For Infinite Cardinals does $A > B \Rightarrow A^C > B^C$?

It seems clear that for $A, B, C$ infinite cardinals with $A > B $ one could define an injection from $B^C \to A^C$ and so $A > B \Rightarrow A^C \ge B^C$, but is the inequality strict and what is the proof ? After reading the counter example my…
Tom Collinge
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When does the cardinality disappear?

Pardon me, if this question sounds stupid. I am learning real analysis on my own and stumbled on this contradiction while reading this -- http://math.kennesaw.edu/~plaval/math4381/setseq.pdf. I appreciate any help or pointers. Consider this example:…
Kamesh
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Mathematics with and without continuum hypothesis

This is a follow-up to a recent question. Are there "interesting" differences between CH-mathematics and (non-CH)-mathematics? Has anybody developed mathematics with c = $\aleph_2$? $\aleph_3$? ... $\aleph_{\omega}$?
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closed unbounded set,regular cardinals,cofinality

Given two regular cardinals $\lambda>\mu$, why this set is a closed unbounded set in $\lambda$? {$\alpha$ | cf($\alpha$)=$\mu$ , $\alpha<\lambda$}
user175304
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cardinal numbers proof

Suppose $a,b$ are cardinals where $a$ is finite and $b$ is infinite. I want to prove that $b^a=b$. The book gives a hint saying to use repeated multiplication of cardinals to do it. I have proved the result using induction and the fact that…
H_B
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Cardinality of Set of Simple Closed Curves

What is the cardinality of the set of all simple closed curves in $R^2$? Furthermore, what resources are there which present a proof, if any, of said cardinality?
analysisj
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cardinality of finite subset

I have the following question: Prove that a set A has the same cardinality of a subset of a Set B, if and only if exists an injective function A to B. I find it hard to prove it because I can easily find a set A which…
Alan
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Name for the sense of how many items are present

Sorry, this might be slightly off topic: there's a word for the ability to look at a small set of items are know how many are there without counting them, but I can't remember what it is and I can't find it on google. Can anyone tell me what this…
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Cardinality of the set of bounded sequences in $\Bbb N$

This is from "Mathematical logic, A course with exercises" Chapter 7 question 7. The question is to determine the cardinality of $\{f\in {\mathbb N}^{\mathbb N}: (\exists p\in \mathbb N)(\forall n\in \Bbb N)(f(n)\le p)\}$ I know this is the set of…
Y.X.
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In cardinal arithmetic does $\alpha ^\beta = \alpha$ for $\beta $ much smaller than $\alpha$?

Given any infinite cardinal $\alpha$ and finite $n$ we have $\alpha^n = \alpha$. Also given any cardinal $\alpha$ of the form $\alpha = \gamma ^ \delta$ for $\delta \le \beta$ we have $$\alpha^\beta = (\gamma ^ \delta)^\beta = \gamma ^{\delta \beta}…
Daron
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Are the number of infinities countable or uncountable?

We have $\aleph_0$, $\aleph_1$, and so on. But why wouldn't there be an $\aleph_\pi$, for example? What is the proof that the types of infinities are a countable set?
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Is there a bijective map between $\mathbb{N}^n$ and $\mathbb{N}$ for $n\in\mathbb{N}$?

I've recently learned that the cardinality of the integers and that of the rationals is the same, as you can map the rationals to the integer grid, draw a spiral that eventually touches every point and label from the centre outwards. If I understand…
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Is the set of all finite sequences of the letters x y z countable?

The question is asking if the set of all finite sequences of the letters x y z is countable. For instance elements such as xyzxyy, yzzxxyyyy, xxxyzyx exist in the set. Would cantors Cantor's diagonal argument work here to prove that the set is…
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General sum and product of cardinal numbers, Koenig‘s theorem, in everyday language

I just read a book’s section about general sums and products of cardinal numbers along with Koenig’s theorem. I made the following summary. The topic is not important to me but I wanna mention it in my notebook, so I try to dense it into natural…
user774814