Questions tagged [complex-analysis]

For questions mainly about theory of complex analytic/holomorphic functions of one complex variable. Use [tag:complex-numbers] instead for questions about complex numbers. Use [tag:several-complex-variables] instead for questions about holomorphic functions of more than one complex variables.

Complex analysis is a branch of mathematical analysis that investigates functions of one or several complex variables. Typical topics include Cauchy's integral formula, singularities, poles, holomorphic and meromorphic functions, Laurent and Taylor series, maximum modulus principle, isolated zeros principle, etc.

Independent variable and dependent variable of complex functions are both complex numbers, and may be separated into real (denoted by $\Re$) and imaginary parts (denoted by $\Im$) : $z = x +iy$ and $w = f(z) =u(x,y)+iv(x,y)$ where $x, y \in \mathbb{R}$, $u(x,y)$ and $v(x,y)$ being real-valued functions.

A fundamental result of complex analysis is the Cauchy-Riemann equations, which give the conditions for a function to have a complex derivative, which is a complex generalization of the (real) derivative. If the complex derivative is defined at each point in an open connected subset of $\mathbb C$, the function is called analytic, or holomorphic. If the complex derivative is defined at each point in $\mathbb C$, the function is called entire.

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Uniform limit of injective analytic functions is injective

I'm stuck on the following problem: Let $f_n$ be a sequence of injective analytic functions on the unit disc $D$ such that $f_n$ converges uniformly to $f$ on compact subsets of $D$. Show that $f$ is either injective or constant. Already $f$ is…
D_S
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Is a meromorphic function always a ratio of two holomorphic functions?

Suppose $D$ is a region (connected open set) in complex plane, and $f$ is a meromorphic function on $D$. Question: Does there always exist two holomorphic function $g$ and $h$ such that $f=\frac{g}{h}$? When $D$ is the whole complex plane I know it…
Yuchen Liu
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Working with $z$, $\overline{z}$ instead of $\operatorname{Re}(z)$, $\operatorname{Im}(z)$

The problem is the following: Determine conditions for $a,b,c\in\mathbb{C}$ such that $az+b\overline{z}+c=0$ has unique solution in $\mathbb{C}$. Teacher answer: If $az+b\overline{z}+c=0$, then…
Gaston Burrull
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Striking applications of Morera's theorem

Morera's theorem is an underappreciated theorem in complex analysis. I have been struck by the simplicity of its proof and some clever applications of it and I had been interested in finding out more of such. Please contribute examples. One example…
user977
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Is analytic capacity continuous from below?

EDIT: I also asked this question on mathoverflow, since it might be too specialized for math.stackexchange.com. I've been wondering about the following, I don't know if anyone knows the answer : For a compact set $K$ in the complex plane, define the…
Malik Younsi
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If $\Re(f)$ is bounded then f is constant.

I have to solve following problem If $\Re (f)$ is bounded above or below for a function $f$ holomorphic on $\mathbb{C}$ then $f$ is constant. My attempt: If there is $M$ such that $\Re(f) \le M$, then $\|e^{f}\|=e^{\Re(f)}\le e^{M}$. From…
3dok
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Detailed proof that no essential singularity at infinity implies polynomial

Suppose $f(z)$ is holomorphic in the whole plane, and that $f(z)$ does not have an essential singularity at $\infty$. Prove that $f(z)$ is a polynomial. I've tried following the hint given in this question. Since $f(z)$ has a nonessential…
PJ Miller
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A bounded holomorphic function

If $\Omega$ is a region which is dense in $\mathbb{C}$, $f\in H(\Omega)$ and is continuous on $\mathbb{C}$, moreover $f$ is bounded on $\mathbb{C}$, can we claim that $f$ is a constant?
Danqing He
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entire bijection of $\mathbb{C}$ with 2 fixed points

Besides the identity map, is there an entire function $f$ that is a bijection from $\mathbb{C}$ to $\mathbb{C}$ and has 2 fixed points? Thank you for the help.
pel
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Analytic functions with nonessential singularity at infinity must be a polynomial

This is an exercise from Alhfors Complex Analysis book- to show that an analytic function with a nonessential singularity at infinity must be a polynomial. It seems like it should probably be pretty straight forward, but I must be missing…
MJoszef
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Derivative and partial derivative of complex functions

I know the formal definition of a derivative of a complex valued function, and how to compute it (same as how I would for real-valued functions), but after doing some problems, I feel as if I could just take the partial derivative w.r.t $x$ of the…
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Complex vs. Real Differentiable

I can follow and understand the algebra in the proof that a $\mathbb{R}$ differentiable function is $\mathbb{C}$ differentaible if and only if the partial$\left(\frac{\partial f}{\partial x}\right)$ -$\frac{1}{i}$ $\left(\frac{\partial f}{\partial…
pad
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Analytic functions defined by integrals

Suppose I define a function using an integral: $$f(z)=\int_{\mathbb R} g(z,x)\ dx,$$ where $g$ is some function, $z$ is a complex variable, and $x$ is a real variable. Suppose the integral exists for $z\in U$, where $U$ is some open region. What are…
Potato
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Help to understand the generalization of the Argument Principle

I'm reading Conway's complex analysis book and I'm trying to prove this theorem left to the reader on page 124: I tried to use integration by parts without success. I need some hint how prove this theorem.
user42912
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Is the complex function $f(z) = Re(z)$ differentiable?

I am preparing to take my first course in complex variables. I am reading some lecture notes online. They claim that the function $f(z) = Re(z)$ is continuous but NOT differentiable. I know the definitions of a limit, of continuity, and of a…