Questions tagged [complex-analysis]

For questions mainly about theory of complex analytic/holomorphic functions of one complex variable. Use [tag:complex-numbers] instead for questions about complex numbers. Use [tag:several-complex-variables] instead for questions about holomorphic functions of more than one complex variables.

Complex analysis is a branch of mathematical analysis that investigates functions of one or several complex variables. Typical topics include Cauchy's integral formula, singularities, poles, holomorphic and meromorphic functions, Laurent and Taylor series, maximum modulus principle, isolated zeros principle, etc.

Independent variable and dependent variable of complex functions are both complex numbers, and may be separated into real (denoted by $\Re$) and imaginary parts (denoted by $\Im$) : $z = x +iy$ and $w = f(z) =u(x,y)+iv(x,y)$ where $x, y \in \mathbb{R}$, $u(x,y)$ and $v(x,y)$ being real-valued functions.

A fundamental result of complex analysis is the Cauchy-Riemann equations, which give the conditions for a function to have a complex derivative, which is a complex generalization of the (real) derivative. If the complex derivative is defined at each point in an open connected subset of $\mathbb C$, the function is called analytic, or holomorphic. If the complex derivative is defined at each point in $\mathbb C$, the function is called entire.

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holomorphic function with special decreasing property

If you consider $f=\frac{P}{Q}$ the quotient of two polynomial function then $\frac{f'}{1+\vert f\vert^2}$ decrease like $\frac{1}{z}$. My question is, is the converse true? is an meromorphic function(define on the whole plane) which…
Paul
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Prove Converse continuity using the Preimages

I would like to prove that if pre images $f^{-1}(U) \subset D $ of open subsets $U\subset \mathbb{C}$ are open in $D$ implies a function $f:D \to \mathbb{C}, D\subset \mathbb{C}$ is continuous. EDIT: I need help with the converse. I thought I had…
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nth roots and logarithm

Suppose $\Omega$ is a region,$f\in H(\Omega)$, and $f\not\equiv 0$.If for every positive integer n,there is $f_n \in H(\Omega)$,$(f_n)^n=f$,prove that there is $g\in H(\Omega),f=e^g$. My conjecture : $$g=lim (nf_n - n)$$ But I don't know how to…
gilliatt
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Proving a function is continuous for a fixed variable

This is from Conway's book: Suppse $f:G \rightarrow \mathbb{C}$ is analytic and define $\phi: G \times G \rightarrow \mathbb{C}$ by $\phi(z,w)=\frac{f(z)-f(w)}{(z-w)}$ if $z \neq w$ and $\phi(z,z)=f'(z)$. Prove that $\phi$ is continuous... Because…
emka
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Why $\lim_{z\to\infty}\frac{\sin(z)}z$ doesn't exist?

I think if we let $t=\frac1z$, then $$\lim_{z\to\infty}\frac{\sin(z)}z=\lim_{t\to0}t\sin(\frac1t)=0$$ but I don't know why in Ablowitz-Fokas Complex Variables, in "Answer to Odd-Numbered Exercises", answer is "doesn't exist"?
user118535
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Consider $f(z)=e^{-z^{-4}}$ for $z≠0$ and $f(0)=0$. Show that the Cauchy Riemann equations are satisfied for $z=0$

Consider $$f(z)=e^{-z^{-4}}$$ for $z≠0$ and $f(0)=0$. Show that the Cauchy Riemann equations are satisfied for $z=0$, and show that $f$ is not complex differentiable. Any smart ideas here ? I hope there is some nicer method than just exanpding…
90intuition
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When does $e^z + e^{-z} = 0$?

Here's what I have so far: Let $e^z + e^{-z} = 0$. Then $e^x\cos y + ie^x\sin y + e^{-x}\cos y - ie^{-x}\sin y = 0$. The simplification in the second term follows because I know $\cos(y) = \cos(-y)$ and $\sin(y) = -\sin(y)$. Am I going about this…
anon_swe
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Show that if $z_0$ is a solution to $(2z-1)^{2014}=(2z+1)^{2014}$, then $\Re(z_0)=0$

Show that if $z_0$ is a solution to $(2z-1)^{2014}=(2z+1)^{2014}$, then $\Re(z_0)=0$. My attempt: $(2z-1)^{2014}=(2z+1)^{2014}\\ \implies \left(\dfrac{2z-1}{2z+1}\right)^{2014}=1=e^{2k\pi i}, k=0\space \ldots \space 2013$ Let $\omega:=e^{2k\pi…
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Show, a holomorphic function with constraint on real and imaginary part is constant

Let $f: G\rightarrow \mathbb{C}$ be a holomorphic function on a domain. Let $\left[\Re{(f)}\right]⁴+\left[\Im{(f)}\right]⁴$ have a local maximum in $G$. Why is $f$ than already constant? If I could show that the absolute of $f$ had a maximum I'd be…
Hagadol
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Limit point of isolated singularities

Suppose $f$ is analytic on $\mathbb{C}$ (or some open domain) except at a sequence $(c_n)$ and its limit point $c$. If each $c_n$ is a removable singularity, what can we say about $c$? While $c$ was not an isolated singularity for $f$, it becomes…
Markus
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Consequence of Riemann mapping theorem

Let $\mathbb{H}$ denote the complex upper half plane (not including the real axis). Let $A$ be a bounded subset with $A = \mathbb{H} \cap \overline{A}$ and $\mathbb{H} \backslash A$ simply connected. Why does it follow from the Riemann mapping…
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Proof of Schwarz Formula

I have a question for homework that asks If $f(z) = u(z) + iv(z)$ is analytic on $\mathbb{D}$ (the open unit disk), and $u(z)$ extends to be continuous on $\overline{\mathbb{D}}$, then $$ f(z) = \int_0^{2 \pi} u(e^{i \theta}) \frac{e^{i \theta} +…
tylerc0816
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Zeros of an entire function

If $f$ is an entire function with $|f(z)|>|f(\bar{z})|$ for all complex numbers $z$ in the upper half plane. How does this imply that $f$ has no zeros in the upper half plane?
lenov
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$f: \mathbb{H} \to \mathbb{C}$ a bounded holomorphic function with $\lim\limits_{\operatorname{Im}(z) \to 0, z \in \mathbb{H}} \mathrm{Re}(f(z))= 0$.

$f: \mathbb{H} \to \mathbb{C}$ a bounded holomorphic function with $\lim\limits_{\operatorname{Im}(z) \to 0, z \in \mathbb{H}} \operatorname{Re}(f(z))= 0$. How does it follow that $f$ is constant? $\mathbb{H}$ is the upper half plane, i. e. $\{ z…
stebu92
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Determining if $f(z)=(1-e^{1/z})^{-1}$ is holomorphic

If we let $$f(z)=(1-e^{1/z})^{-1} ,$$ where $z$ is complex, I'm trying to use the Cauchy-Riemann equations to determine if $f$ is holomorphic. So I need to separate it into real and imaginary functions of $x$ and $y$ ($u(x,y)$ , $v(x,y)$…
Freeman
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