Questions tagged [continuity]

Intuitively, a continuous function is one where small changes of input result in correspondingly small changes of output. Use this tag for questions involving this concept. As there are many mathematical formalizations of continuity, please also use an appropriate subject tag such as (real-analysis) or (general-topology)

Analytic Definition: Let $(X, d_X)$ and $(Y, d_Y)$ be metric spaces. A map $f : X \to Y$ is said to be continuous at $x_0$ if for every $\varepsilon > 0$, there is $\delta > 0$ such that $d_Y(f(x_0), f(x)) < \delta$ whenever $d_X(x_0, x) < \varepsilon$. A map $f : X \to Y$ is said to be continuous if it is continuous at $x_0$ for all $x_0 \in X$.

Topological Definition: Let $(X,\mathcal T_X)$ and $(Y, \mathcal T_Y)$ be topological spaces. A map $f : X \to Y$ is said to be continuous if $U \in \mathcal T_Y$ implies that $f^{-1}(U) \in \mathcal T_X$.

In the case of metric spaces, the metric induces a topology, and the two notions of continuity coincide. Note that multiple metrics can induce the same topology, and that not all topologies are metrizable (can be generated from some metric).

Continuity is a sufficient condition for the intermediate value theorem. It is also a necessary condition for the extreme value theorem, as well as differentiability.

17100 questions
0
votes
1 answer

Let $f : \mathbb{R} \rightarrow \mathbb{R} $ with intermediate value property and increasing over $ \mathbb{R} $ \ $\mathbb{Q}$.

Let $f : \mathbb{R} \rightarrow \mathbb{R} $ with intermediate value property and increasing over $ \mathbb{R} $ \ $\mathbb{Q}$. Then $f$ is continous on $\mathbb{R}$. How to try?
Almath
  • 213
0
votes
1 answer

Is it correct to say that h(x) is a function whose continuity depends on just the rational function finally it forms and not of f(g(x)) discontinuity?

If $f(x)=\frac{1}{(x-2)(2x-5)}$ and $g(x)=\frac{1}{x^2}$ , we define $f(g(x))$ over the domain in which its defined , is it correct to say $f(g(x))$ is discontinuous at $+-√(2/5)$ ,$0$ and +-$1/√2$ ? $0$ because the input is going into $g(x)$ hence…
0
votes
0 answers

Continuity of Dirichlet Function

I am confused if the dirichlet function is continuous at 0 or nowhere continuous. This answer on MSE says it's continuous at 0 Example of a function continuous at only one point. The Wikipedia page says it's nowhere continuous:…
0
votes
0 answers

Is this a counterexample to show that the image of a hausdorff space under a continuous map ist not Hausdorf anymore?

I have the following problem: I need to prove or give a counterexample for the following claim: The image of a Hausdorff space under a continuous map is Hausdorff. I claimed that this is wrong and I gave the following example. Take…
user1294729
  • 2,008
0
votes
0 answers

Prove $\sqrt{x(y-1)^2}$ if $x(y-1)^2\geq0$, $0$ if $x(y-1)^2<0$ is continuous in $R^2$

\begin{equation} f(x,y) = \left\{ \begin{array}{l l} \sqrt{x(y-1)^2}, \quad x(y-1)^2 \geq 0\\ 0, \quad x(y-1)^2 <0 \\ \end{array} \right\} \end{equation} It is clear to me how to prove where…
0
votes
0 answers

How do I compute the degree of this function?

I have the following problem: Let $f,g:S^1\rightarrow S^1$ be continuous mags with degree $\deg(f), \deg(g)$. Compute the degree of $g\circ f$ I first denoted $\deg(f)=n$ and $\deg(g)=m$. Then I know that f and g are homotopic to $z\mapsto…
user123234
  • 2,885
0
votes
1 answer

What does it mean if a map corresponds to a path?

I am solving an exercise and they wrote the following: Let $f,g:S^1 \rightarrow U\subset \mathbb{R}^2$ be continous maps corresponding to paths $\gamma_f,\gamma_g:[0,1]\rightarrow U$ I somehow don't understand what this means. So we know that…
user1294729
  • 2,008
0
votes
1 answer

Primitivable function

Let $f \colon\mathbb R \rightarrow \mathbb R $ be an increasing function. Define $F\colon \mathbb R \rightarrow \mathbb R $ as $$F(x)=\lim_{y \downarrow x}f(y), \text{ for every }x \in \mathbb R.$$ Prove that if $F$ is continuous then $f$ is…
0
votes
2 answers

Can a function be inexistent at the origin but still be continuous there?

I have: \begin{equation} f_1(x,y)=\frac{xy}{(x^2+y^2)^{\frac{1}{2}}} \end{equation} Is this function continuous at the origin, still it does not exist there? Thanks
Luthier415Hz
  • 2,739
  • 6
  • 22
0
votes
1 answer

I cannot determine if this function is continuous

Consider the function \begin{align*} f(x) = \frac{x^{3} - x^{2}}{x-1} \end{align*} This function is not continuous at $x = 1$. However, using factorization, this function is equal to $ \begin{align*} f(x) = \frac{x^2(x-1)}{x-1} =…
AAA
  • 19
0
votes
1 answer

What does it mean that you can "nudge" an open interval $(a,b)$ so that function is defined at $a$ and $b$?

In this question on continuity, the OP says, ...an open interval would allow a left and right limit to exist since the limit can approach from both sides, correct? and ...you can always mark off a little interval around it where that interval is…
Doobius
  • 336
0
votes
1 answer

f(x) = $1/\sqrt{1-|x|}$ + $1/x^4$. Using the intermedia value theorem, prove that $f(x) = 123$ has at least one solution

$$f(x) = \frac{1}{\sqrt{1-|x|}} + \frac{1}{x^4}$$ show that $f(x) = 123$ has at least one answer. I have so far worked out the interval at which the function is continuous $(-1,0)\cup(0,1)$ The function is continuous everywhere except when $x>1$ and…
Indigo
  • 11
0
votes
1 answer

Intermediate Value Theorem (continuity)

By using the Intermediate value theorem. Show that f is continuos on $[-1,1]$, then there exist n in the natural numbers such that the equation $f(x) + n = n(e^x)$ has a solution in $[-1,1]$. I'm having trouble solving this problem. Any help is…
0
votes
1 answer

A question on continuity of disjoint closed intervals

So, the question is which one of the following is true? a) There exists a continuous function from $[-\pi/2,\pi/2]$ onto $(0,1)$ b) There exists a continuous function from $[-\pi/2,\pi/2]$ onto R c)There exist a continuos function from…
Natasha J
  • 825
0
votes
2 answers

Let $f:\Bbb R \to \Bbb R$ be a continuous function satisfying $f(x)=f(x+1) \forall x\in \Bbb R$. Then which of the following is true.

Let $f:\Bbb R \to \Bbb R$ be a continuous function satisfying $f(x)=f(x+1) \forall x\in \Bbb R$. Then (A) $f$ is not necessarily bounded above. (B) there exists a unique $x_{0} \in R$ such that $f(x_{0} + \pi) = f(x_{0}).$ (C) there is no $x_{0} \in…
Shubham
  • 33